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LiRa [457]
3 years ago
8

Why are some rocks smooth and others rough?

Physics
1 answer:
klemol [59]3 years ago
6 0
It all depends on where the rock was found or former, often rocks in the ocean are smoother due to the strong currents over time while on land rocks tend to be rough but yet again it all depends on the location
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A car travels 60 miles due West first then turns back and travels 120 miles due East in 3 hours. What is...
ella [17]

Answer:

<h2>A. 180 miles</h2><h2>B. 60 miles</h2><h2 />

Explanation:

In this problem, we are required to solve for the total distance that the car travelled. and the displacement

A) the distance travelled by car

this can be gotten by summing all the distances the car has travelled.

i,e total distance= 60 miles+120 miles

total distance= 180 miles

B) the displacement of the car

the displacement can be gotten by  subtracting the final distance from the initial distance

final distance = 120 miles

initial distance= 60 miles

displacement= 120-60= 60 miles

7 0
3 years ago
A lemming running 2.22m/s runs off a horizontal cliff. It lands in the water 7.45m from the base of the cliff. How much time was
Gelneren [198K]
3,56.........................
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4 years ago
Will give correct answer brainliest
levacccp [35]
The potential energy= mass times gravity times height. However, we are missing height. Gravity is a constant that is 9.8 on Earth. We then solve for height by dividing 350 by 10 and then 9.8 to get about 3.5.
TLDR: 3.5
3 0
3 years ago
Read 2 more answers
the hot gas lines need to be insulated? A never B always C if they are exposed to cold temperatures that could cause the refrige
muminat
The answer is a because it never needs to be insulated
8 0
3 years ago
A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of
Rudiy27

Answer:

Explanation:

Given

mass of spring m=100\ gm

extension in spring x=5\ cm

downward velocity v=70\ cm/s

Position in undamped free vibration is given by

u(t)=A\cos \omega _0t+B\sin \omega _0t

where \omega _0^2=\frac{k}{m}

also \frac{k}{m}=\frac{g}{L}

\omega _0^2=\frac{k}{m}=\frac{9.8}{0.05}

\omega _0=14

u(t)=A\cos(14t)+B\sin(14t)

it is given

u(0)=0

u'(0)=70\ cm/s

substituting values we get

A=0

u(t)=B\sin (14t)

u'(t)=14B\cos (14t)

70=14B

B=\frac{10}{2}

B=5

u(t)=5\sin (14t)

3 0
3 years ago
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