The equation to be used is for the rectilinear motion at constant acceleration:

x = v₀t + 0.5at²
a = (v-v₀)/t
where
x is distance
v and v₀ is the final and initial velocity
t is time
a is acceleration

Because the acceleration is decelerating, that would be reported as -7.5 m/s². Substituting,

-7.5 = (0 - v₀)/t
v₀ = 7.5 t --> eqn 1

x = v₀t + 0.5at²
60 = (7.5t)(t) + 0.5(-7.5)(t²)
Solving for t,
t = 4s

Thus,
v₀ = 7.5 m/s² * 4s
v₀ = 30 m/s

6 0

2 years ago

Jason took 6 hours to travel 540 km. For the first 140 km, he

inessss [21]

Answer: 100

Explanation:

7 0

2 years ago

Calculate the force of gravity between a 2.50 kg newborn baby and a 80.0 kg doctor standing 0.250 m away. G = 6.67 E -11 N*m2/kg

Alex787 [66]

Answer: 2.13 × 10⁻⁷ N

Explanation:

Gravitational force exists between any two bodies having mass.

Force of gravity is given by:

$F =G\frac{Mm}{r^2}$

It is given that, mass of newborn baby is M = 2.50 kg

Mass of the doctor, m = 80.0 kg

Distance between the two, r = 0.250 m

Gravitational constant, G = 6.67 × 10⁻¹¹ N m²/kg²

⇒F = (6.67 × 10⁻¹¹ N m²/kg² × 2.50 kg × 80.0 kg )÷ (0.250 m)² = 2.13 × 10⁻⁷ N

Thus, the force of gravity between new born baby and doctor is 2.13 × 10⁻⁷ N.

7 0

2 years ago