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kondor19780726 [428]
3 years ago
8

Firecrackers A and B are 600 m apart. You are standing exactly halfway between them. Your lab partner is 300 m on the other side

of firecracker A. You see two flashes of light, from the two explosions, at exactly the same instant of time. Define event 1 to be firecracker A explodes and event 2 to be firecracker B explodes. According to your lab partner, based on measurements he or she makes, does event 1 occur before, after, or at the same time as event 2? Explain
Physics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

Explanation:

A and B are 600 m apart . firecrackers explodes and make two waves , sound waves and light waves . they spread  out on all sides . The person sitting in the middle , observes two lights simultaneously and after some time hears two sound simultaneously . It is so because waves coming from A and B covers equal distance to reach the middle point . Same will be the case for sound waves .

But for observer sitting on the other side of A , both light and sound wave will not reach simultaneously . Light wave coming from A will reach earlier because distance covered by light will be less . Similarly sound coming from A will reach earlier . So he / she will observe cracker at A to have exploded earlier than that at B .

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the SI and CGS unit of force are newton and dyne respectively haow many dynes are equal to one newton​
Triss [41]

Answer:

For example, the CGS unit of force is the dyne, which is defined as 1 g⋅cm/s2, so the SI unit of force, the newton (1 kg⋅m/s2), is equal to 100000 dynes.

Explanation:

5 0
3 years ago
A skateboarder shoots off a ramp with a velocity of 5.1 m/s, directed at an angle of 55° above the horizontal. The end of the ra
ExtremeBDS [4]

Answer

given,

initial velocity of skateboard = 5.1 m/s

angle above the horizontal = 55°

height of the ramp = 1 m

a) maximum height of projectile

  H = \dfrac{u^2sin^2 \theta}{2g}

  H = \dfrac{5.1^2\times sin^2 55^0}{2\times 9.81}

         H =  0.889 m

the maximum height of the skateboard above the ground

         = 1 + 0.889

         = 1.889 m

b) time to reach the height

   t = \dfrac{u\ sin\theta}{g}

   t = \dfrac{5.1\ sin55^0}{9.8}

          t = 0.426 s

horizontal distance = u cos θ × t

                                = 5.1 × cos 55° × 0.426

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7 0
3 years ago
A uniform electric field is directed parallel to the +y axis. If a positive test charge begins at the origin and moves upward al
lukranit [14]

Answer: option 1 : the electric potential will decrease with an increase in y

Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below

V = kq/y

Where k = 1/4πε0

Where V = electric potential,

k = electric constant = 9×10^9,

y = distance of potential relative to a reference point, ε0 = permittivity of free space

q = magnitude of electronic charge = 1.609×10^-19 c

From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.

We have that

V = k/y

We see the potential(V) is inversely proportional to distance (y).

This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.

This fact makes option 1 the correct answer

3 0
3 years ago
A vector is 14.4 m long and
MaRussiya [10]

Answer:

Explanation:

The x-component is found in the magnitude of the vector times the cosine of the angle.

A_x=14.4cos133 and, to 3 sig dig,

A_x=-9.82m

3 0
3 years ago
Watt-hours is a measure of energy, just like kilowatt-hours. How can you convert this to Joules?
satela [25.4K]

Work with your units:

1 watt-hour = 1 (joule/second) · (hour) = 1 (joule-hour / second)

(1 joule-hour/sec) · (3600 sec/hour) = 3600 joules

So 1 watt-hour = 3,600 joules

3 0
3 years ago
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