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snow_tiger [21]

3 years ago

5

ASAP Even though the force exerted on each object in a collision is the same strength, if the objects have different masses, the

ir will be different. * O changes in velocity O amount of force O speed and direction

1 answer:

tatuchka [14]3 years ago

8 0

Answer:

it should be changes in velocity

Explanation:

I hope this helps!

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Some folded mountains result from the collision of continental plates. <br> a. True<br> b. False

alexgriva [62]

it true be cause when one goes under another the ground rise and makes what we call a mountain so therefore it is treu<span />

3 0

3 years ago

A man weighing 720 N and a woman weighing 500 N have the same momentum. What is the ratio of the man's kinetic energy Km to that

tiny-mole [99]

Answer:

Because weight W = M g, the ratio of weights equals the ratio of masses.

(M_m g)/ (M_w g) = [ (p^2 Man )/ (2 K_man)] / [ (p^2 Woman )/ (2 K_woman)

but p's are equal, so

K_m/K_m = (M_w g)/(M_m g) = W_woman / W_man = 450/680 = 0.662Explanation:

4 0

3 years ago

Describe a car's velocity as it goes around a track at a constant speed

igor_vitrenko [27]

If the car is going at constant speed than the velocity isnt changing, only the direction of velocity.

4 0

3 years ago

An air-filled parallel-plate capacitor is connected to a battery and allowed to charge up. Now a slab of dielectric material is

natita [175]

Answer:

The charge on the capacitor had increased

Explanation:

The expression for the capacitance of an air-filled parallel-plate capacitor is as follows as;

$C=\frac{\epsilon _{0}A}{d}$

Here, C is the capacitance, $\epsilon _{0}$ is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.

When a slab of dielectric material is placed between the plates of the capacitor then the expression for the capacitance is as follows;

$C=\frac{K\epsilon _{0}A}{d}$

Here, K is the dielectric constant.

In the given problem, a slab is inserted between the plates of the capacitor then the capacitance of the capacitor will increase in this case. Therefore, the option (a) is true.

The expression for the charge stored in the capacitor is as;

Q= CV

Here, Q is the charge and V is the potential.

The charge will also increase in this case as the charge stored in the capacitor is directly proportional to the capacitance. Therefore, the option (d) is not true.

The expression for the energy stored in the capacitor is as follows;

$E=\frac{CV^{2}}{2}$

The voltage is constant in the given problem but the capacitance increases then the energy stored in the capacitor will increase. Therefore, the option (b) is not true.

The voltage across the capacitor will remain same as the capacitor is still connected to the battery. Therefore, the option (c) is not true.

Therefore, only option (a) is true.

3 0

3 years ago

Calculate the ph of the solution that results following addition of 24 ml of 1.0 mnaoh to 60 ml of 1.0 mnh4cl.

Lostsunrise [7]

The pH of the solution is 0.37.

<h3>What is the pH of the solution?</h3>

We can write the equation of the reaction as;

$NH4Cl (aq) + NaOH (aq) ------- > NH3 (aq) + H2O (l) + NaCl (aq)$

Number of moles of $NaOH$ = 24/1000 * 1 = 0.024 moles

Number of moles of $NH4Cl$ = 60/1000 * 1 = 0.060 moles

Given that the reaction is 1:1, the limiting reactant is NaOH

Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles

Concentration of left over NH4Cl = 0.036 moles/(24 + 60)/1000

= 0.43 moles

pH = -log(0.43)

pH = 0.37

Learn more about pH:brainly.com/question/15289741

#SPJ1

4 0

2 years ago