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1 year ago

consider a charged parallel-plate capacitor. which combination of changes would quadruple its capacitance?

Physics

1 answer:

kogti [31]1 year ago

4 0

Its capacitance Double the charge and double the plate area.

Doubling the distance between the plates of a capacitor double the capacitance. Doubling the distance between the plates of a capacitor quadruples the capacitance. As the distance between the plates decreases, the capacitance increases because the potential difference decreases.

Halving the distance between the plates of a parallel plate capacitor doubles the capacitance of the capacitor from its initial capacitance. When two or more capacitors are connected in parallel, the overall effect is that of a single equivalent capacitor with the sum of the plate areas of the individual capacitors. As we saw earlier all other factors being equal, more disk space equals more capacity.

Learn more about Capacitor here:-brainly.com/question/27393410

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The purpose of the fraud fighter/ black light machine is to:

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The purpose of the fraud fighter or also known as black light machine is that it has the ability to check counterfeited bills. It is designed to be a detector with the counterfeited bills, plus, it is a way of verification. It is composed of a UV light, where in, making it have the ability to detect the counterfeited bills which is its task to do.

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3 years ago

A 5.00 kg rock whose density is 4300 kg/m3 is suspended by a string such that half of the rock's volume is under water. You may

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Answer:

The tension on the string is $T = 43.302 \ N$

Explanation:

From the question we are told that

The mass of the rock is $m_r = 5.00 \ kg = 5000 \ g$

The density of the rock is $\rho = 4300 \ kg/m^3 = 4.3 g/dm^3$

Generally the volume of the rock is mathematically evaluated as

$V = \frac{m_r}{\rho}$

substituting values

$V = \frac{5000}{4.3}$

$V = 1162.7 \ dm^3$

The volume of the rock immersed in water is

$V_w = \frac{V}{2}$

substituting values

$V_w = \frac{1162.7 }{2}$

$V_w = 581.4 \ dm^3$

mass of water been displaced by the this volume is

$m_w = V_w$ According to Archimedes principle

=> $m_w = 581.4 \ g$

$m_w = 0.5814 \ kg$

The weight of the water displace is

$W _w = m_w * g$

$W _w = 0.5814 * 9.8$

$W _w = 5.698 \ N$

The actual weight of the rock is

$W_r = m_r * g$

$W_r = 5.0 * 9.8$

$W_r = 49.0 \ N$

The tension on the string is

$T = W_r - W_w$

substituting values

$T = 49.0 - 5.698$

$T = 43.302 \ N$

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3 years ago

Bowen’s reaction series illustrates relations between:

Finger [1]

C. Temperature, chemical composition and mineral structure

Explanation:

The Bowen's reaction series illustrates the relationship between temperature, chemical composition and mineral structure.

The series is made up of a continuous and discontinuous end through which magmatic composition can be understood as temperature changes.

The left part is the discontinuous end while the right side is the continuous series.
From the series, we understand that a magmatic body becomes felsic as it begins to cool to lower temperature.
A magma at high temperature is ultramafic and very rich in ferro-magnesian silicates which are the chief mineral composition of olivine and pyroxene. These minerals are predominantly found in mafic- ultramafic rocks. Also, we expect to find the calcic-plagioclase at high temperatures partitioned in the magma.
At a relatively low temperature, minerals with frame work structures begins to form . The magma is more enriched with felsic minerals and late stage crystallization occurs here.

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