<h2>
Answer:</h2>
18m
<h2>
Explanation:</h2><h2>
</h2>
Diagrammatically represent the information as follows;
E
/|
/ |
/ |
/ |
B <u>/)25° |C</u>
| |
1.7m | |
A <u>| |D</u>
35.0m
<em>As shown in the figure above;</em>
<u>AB</u> represents the distance from his feet to his eyes = 1.7m
<u>AD</u> represents the distance from his feet to the foot of the flag pole = 35.0m
∠EBC represents the angle from his eyes to the top of the flag pole = 25.0°
<u>ED</u> is the height of the flag pole.
<em>To get the height (ED) of the flag pole;</em>
<em>(i) First calculate </em><em><u>EC</u></em><em> using the tangent trigonometric function as follows;</em>
tan θ = opposite / adjacent --------------------(i)
Where;
θ = ∠EBC = 25.0°
opposite = <u>EC</u>
adjacent = <u>BC</u> = <u>AD</u> = 35.0m
<em>Substituting these values into equation (i) gives;</em>
tan 25.0° = EC / 35.0
0.4663 = EC / 35.0
<em>Solve for EC;</em>
EC = 0.4663 x 35.0
EC = 16.3m
<em>(ii) Then, add EC and CD to give ED (which is the height of the pole).</em>
i.e
ED = EC + CD (where CD = AB = 1.7m)
ED = 16.3 + 1.7
ED = 18m
Therefore the height of the flag pole is 18m