GPE= height x mass x gravitational field strength
5 x 10 x 9,8=490J
Answer:
Option A. 4 m
Explanation:
Please see attached photo for diagram.
In the attached photo, X is the distance from the centre to which the student on the right must sit in order to balance the seesaw.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
Divide both side by 45
X = 180 / 45
X = 4 m
Thus, the student must sit at 4 m from the centre.
Answer:
W = 882.9[J]
Explanation:
In order to be able to calculate the work, we must first calculate the force necessary to lift the box. Since the necessary force is equivalent to the weight of the box, we can determine the weight of the box by means of the product of mass by gravitational acceleration.

where:
w = weight [N]
m = mass = 30 [kg]
g = gravity acceleration = 9.81 [m/s²]
![w = 30*9.81\\w = 294.3 [N]](https://tex.z-dn.net/?f=w%20%3D%2030%2A9.81%5C%5Cw%20%3D%20294.3%20%5BN%5D)
Now, the work can be calculated multiplying the force (weight) by the distance [m]
![W = w*d\\W = 294.3*3\\W=882.9[J]](https://tex.z-dn.net/?f=W%20%3D%20w%2Ad%5C%5CW%20%3D%20294.3%2A3%5C%5CW%3D882.9%5BJ%5D)
Answer:
The bystander will hear a frequency of 931.18 Hz.
Explanation:
let V = 39.5 m/s be velocity of the police car and Fs be the frequency a siren of the police car emits. let v = 0 m/s be the velocity of the bystander and Vs = 340 m/s is the velocity of sound in air.
then, we know that the bystander has to hear a higher frequency than the one emitted and the frequency that the bystander hears is given by the doppler relation:
Fo = [(Vs)/(Vs - V)]×Fs
= [(Vs)/(Vs - V)]×Fs
= [(340)/(340 - 39.5)]×(823)
= 931.18 Hz
Therefore, the bystander will hear a frequency of 931.18 Hz.