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saveliy_v [14]
4 years ago
15

A 50-turn circular wire loop has a radius 3 cm and is located in a uniform magnetic field. The magnetic field lines are perpendi

cular to the plane of the circular loop. Suppose that the magnetic field is varied so that BBB increases from 0.1 T to 0.35 T in 1.95 ms. Part A Find the average induced emf in the coil (including sign of the emf). View Available Hint(s)
Physics
1 answer:
Maru [420]4 years ago
3 0

Answer:

Average induced emf = - 18.13 V

Explanation:

According to Faraday's law of electromagnetic induction,

Induced emf = - N (dΦ/dt)

Φ = magnetic flux = BA

(dΦ/dt) = A(dB/dt)

Emf = -NA (dB/dt)

Average induced emf = - NA (ΔB/Δt)

N = number of turns = 50 turns

A = Cross sectional Area of the circular loop = πr² = π(0.03)² = 0.00283 m²

ΔB = Change in magnetic field strength = 0.35 - 0.1 = 0.25 T

Δt = 1.95 ms = 0.00195 s

Average induced emf = - (50)(0.00283)(0.25/0.00195)

Average induced emf = - 18.13 V

The minus sign indicates that the average induced emf and the change in magnetic flux have opposite signs.

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8 0
1 year ago
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3 years ago
When there is no number in front of a chemical formula in a chemical equation, what number is understood?
Andre45 [30]
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5 0
4 years ago
A pebble is thrown into the air with a velocity of 19/m at an angle of 36 with respect to the horizontal.
kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

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The angle the projectile path of the pebble makes with the horizontal, θ = 36°

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