Examine the nuclear reaction: Superscript 1 subscript 1 H plus superscript 1 subscript 0 n right arrow superscript 2 subscript 1
2 answers:
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Answer
given,
frequency from Police car= 1240 Hz
frequency of sound after return = 1275 Hz
Calculating the speed of the car = ?
Using Doppler's effect formula
Frequency received by the other car
..........(1)
u is the speed of sound = 340 m/s
v is the speed of the car
Frequency of the police car received
now, inserting the value of equation (1)
1.02822(340 - v) = 340 + v
2.02822 v = 340 x 0.028822
2.02822 v = 9.799
v = 4.83 m/s
hence, the speed of the car is equal to v = 4.83 m/s
Answer:
The jet will fly 2400 km.
Explanation:
Given the velocity of the jet flying toward the east is 1,500 kmph toward the east.
We need to find the distance covered in 1.6 hours.
In our problem we are given speed and time, we can easily determine the distance using the following formula.
So, the supersonic jet will travel 2400 km in 1.6 hours toward the east from its starting point.