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Anon25 [30]
3 years ago
6

Deforestation typically

Chemistry
1 answer:
harkovskaia [24]3 years ago
8 0
<span>B. increases erosion in an area</span>
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Calculate the standard cell potential at 25 ∘c for the reaction x(s)+2y+(aq)→x2+(aq)+2y(s) where δh∘ = -793 kj and δs∘ = -319 j/
QveST [7]
First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
        = - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts   
 
5 0
3 years ago
What are the correct half reactions for the following reaction:
d1i1m1o1n [39]

Answer:

D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.

Explanation:

  • It is a redox reaction that is consisted of two half-reactions:

Oxidation reaction:

Zn losses 2 electrons and is oxidized to Zn²⁺:

<em>Zn → Zn²⁺ + 2e⁻.</em>

<em></em>

Reduction reaction:

H⁺ gains 1 electron and is reduced to H:

<em>2H⁺ + 2e⁻ → H₂.</em>

<em></em>

<em>So, the right choice is: D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.</em>

<em></em>

8 0
3 years ago
Read 2 more answers
How would you prepare a 35 ml solution of 95% (volume/volume solution of ethanol?
Artyom0805 [142]

Explanation:

<em><u>Solutions. 1. If 47 g of KCl dissolved in enough water to give 375 mL of soloution, what is the molarity ... vo volume of solute . ... v/v ethanol, how much 95% v/v ethanol ... prepare 200. mL ...</u></em>

7 0
3 years ago
The si unit for distance is ?
ipn [44]
The SI unit for distance is metres - m.

The SI unit for speed or velocity is metres per second - m/s.

The SI unit for acceleration is metres per second squared. - m/s^2.
6 0
3 years ago
Read 2 more answers
Explain the difference in the boiling point of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity an
Len [333]
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.

As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.

The Interactions found in these compounds are London Dispersion Forces.

And among several factors at which London Dispersion Forces depends, one is the size of molecule.

Size of Molecule:
                          There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
6 0
3 years ago
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