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rjkz [21]
3 years ago
10

Natural gas, which you may assume to be pure methane, is burned in a furnace for space-heating purposes. (a) If twice the minimu

m of air is used for the combustion, and if the methane and air are initially at 20 C and the stack gases, including all of the water and vapor, are at 100 C, how much heat is liberated per mole of methane burned
Chemistry
1 answer:
Sergio [31]3 years ago
3 0

Answer:

no no no no no no no no no no no no no no

You might be interested in
Carbon dioxide and helium which has a higher van der waals force of attraction between molecules ​
raketka [301]

Answer:

Carbon dioxide  

Explanation:

Neither helium nor carbon dioxide has a molecular dipole, so their strongest van der Waals attractive forces are London forces.

Helium is a small spherical atom with only a two electrons, so its atoms have quite weak attractions to each other.

CO₂ is a large linear molecule. It has more electrons than helium, so the attractive forces are greater. Furthermore, the molecules can align themselves compactly side-by-side and maximize the attractions (see below).

For example. CO₂ becomes a solid at -78 °C, but helium must be cooled to -272 °C to make it freeze (that's just 1 °C above absolute zero).

7 0
3 years ago
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
How did oxygen first enter Earth's atmosphere?
forsale [732]

Answer:

I think c biological processes

8 0
3 years ago
Describe what half-life is.<br> answer in a paragraph please.
dangina [55]

Half-life is defined as the quantity to reduce to half of its initial value.

Explanation:

The term half-life is generally used in nuclear physics which describes how long a stable atom can survive a radioactive decay or how quickly an unstable stable atom can undergo radioactive decay. Half-life is a constant and does not have any units.

<u>The formula to calculate half-life: </u>

N(t) = \bold{N_{0} e^{-\lambda t}}

Here N(t) is the quantity which is “not decayed”.

N_0 is the “initial quantity” of the substance.

λ is the “decay constant”

4 0
4 years ago
When aqueous solutions of AgNO 3 and KI are mixed, AgI precipitates. The balanced net ionic equation is ________. Ag (aq) I- (aq
dimulka [17.4K]

Answer:

Ag⁺(aq) + Cl⁻(aq) ==> AgCl(s)

Explanation:

The net ionic equation can be described as the equation that contains only those species which would be participated in the chemical reaction. The spectator ions are the type of the ions that are present in both sides of the chemical equation these ions could not be present in the net ionic equation

First, it is easiest if you write the compete molecular equation:

AgNO₃(aq) + KCl(aq) ⇔ AgCl(s) + KNO₃(aq)

we look up which compounds are soluble (aq) and which are not (s). In this case, silver chloride (AgCl) is not soluble.  Thus, the net ionic equation is...  

Ag⁺(aq) + Cl⁻(aq) ==> AgCl(s)

5 0
3 years ago
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