Answer:
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Answer:
<h3>0.329m/s</h3>
Explanation:
According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the respective initial velocities
v is the final velocity
Given
m1 = 0.190kg
u1 = 1.5m/s
m2 = 0.305kg
u2 = -0.401m/s
Substitute
0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v
0.285 - 0.122305 = 0.495v
0.162695 = 0.495v
v = 0.162695 /0.495
v = 0.329m/s
<em>Hence their velocities after collision is 0.329m/s in the positive x direction</em>
<em></em>
Vi = 2m/s
a= 4.5 m/s
d= 340 m
vf= ?
use this equation ... vf^2=vi<span>^2+2ad
you should get vf = 55.3
hope this helps </span>
