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erastova [34]
3 years ago
5

Question #6a) You were told to assume that the ball bounced to a height of 1.2 m and that the distance between the bounces measu

red along the floor was 0.5 m. Assume that the height of the bounce were less than before, but the distance between bounces were still the same, and complete the following predictions.The horizontal velocity would be (greater/same/less) before.The time between bounces would be (greater/same/less) before.The magnitude of the acceleration of the ball would be (greater/same/less) before.The maximum vertical velocity (right after the first bounce) would be (greater/same/less) before.b) Which of the following statements are evidence that the motion in the x and y coordinates can be treated separately? Select each accordingly.Evidence/NOT evidence : From the graphs of x(t) and y(t), we can see that acceleration happens only in the y coordinate.Evidence/NOT evidence : The time of flight of a bounced ball depends only on the initial y velocity after the first bounce.Evidence/NOT evidence : The acceleration of free-fall is constant.Evidence/NOT evidence : It takes the same amount of time for a dropped ball to reach the floor as it does for a ball that is launched horizontally from the same height.Evidence/NOT evidence : The component equations of x(t) and vx(t) contain no functions of y or vy, and the component equations of y(t) and vy(t) contain no functions of x or vx.Evidence/NOT evidence : A line fit to vy(t) can be used to find the acceleration in the y direction.
Physics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

Explanation:

In the problem they give the case of a ball that bounces on the vertical axis the height is getting smaller, on the x axis it is the same distance all the time.

Questions about the aspect of the x-axis

- Since the distance traveled between the rebounds is the same, the speed must be the same or constant throughout the entire journey.

- Since the distance and speed are equal, the time between rebounds is the same

- There can be no acceleration because the bounce gap should change, the acceleration is zero all the time

Questions about the Y axis

- The vertical speed of the first boat would be the greatest of all, so it has the highest height

b) Evidence or not Evidence

1  evidence, because the graphs are different, one is a straight line and he gives a parable

2 no evidence, nothing involved on the x axis

3  no evidence, the acceleration on the y axis is independent of the acceleration on the x axis

4  no evidence, the time that is cast is the only change that is the same for both movements

5  evidence, the fact that no mixture of components is found allows the variable to be separated into different equations

6  no evidence, says nothing about the x-axis

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Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fi
ehidna [41]

Answer:

The tabletop is smooth so my finger is down it fast and easy. The fabric however slowed my finger down considerably, and it was harder for me to move my finger across it.

Explanation:

Hope this helps.

3 0
2 years ago
Sandy is whirling a ball attached to a string in a horizontal circle over his head. If Sandy doubles the speed of the ball, what
jeka57 [31]

The tension in the string B) It quadruples.

Explanation:

The ball is in uniform circular motion in a horizontal circle, so the tension in the string is providing the centripetal force that keeps the ball in circular motion. So we can write:

T= m\frac{v^2}{r}

where:

T is the tension in the string

m is the mass of the ball

v is the speed of the ball

r is the radius of the circle (the lenght of the string)

In this problem, we are told that the speed of the ball is doubled, so

v' = 2v

Substituting into the previous equation, we find the new tension in the string:

T' = m \frac{(2v)^2}{r}=4(m\frac{v^2}{r})=4T

Therefore, the tension in the string will quadruple.

Learn more about circular motion:

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6 0
3 years ago
From mechanics, you may recall that when the acceleration of an object is proportional to its coordinate, d2xdt2=−kmx=−ω2x , suc
marysya [2.9K]

Answer:

    q = q₀ sin (wt)

Explanation:

In your statement it is not clear the type of circuit you are referring to, there are two possibilities.

1) The circuit of this problem is a system formed by an Ac voltage source and a capacitor, in this case all the voltage of the source is equal to the voltage at the terminals of the capacitor

                    ΔV = ΔV_{C}

we assume that the source has a voltage of the form

                    ΔV = ΔV₀o sin wt

The capacitance of a capacitor is

                   C = q / ΔV

                  q = C ΔV sin wt

the current in the circuit is

                    i = dq / dt

                    i = c ΔV₀ w cos wt

if we use

                  cos wt = sin (wt + π / 2)

we make this change by being a resonant oscillation

we substitute

                  i = w C ΔV₀ sin (wt + π/2)

With this answer we see that the current in capacitor has a phase factor of π/2 with respect to the current

2) Another possible circuit is an LC circuit.

In this case the voltage alternates between the inductor and the capacitor

                     V_{L} + V_{C} = 0

                      L di / dt + q / C = 0

the current is

                      i = dq / dt

                       

they ask us for a solution so that

                    L d²q / dt² + 1 / C q = 0

                     d²q / dt² + 1 / LC q = 0

this is a quadratic differential equation with solution of the form

                    q = A sin (wt + Ф)

to find the constant we derive the proposed solution and enter it into the equation

                di / dt = Aw cos (wt + Ф)

                d²i / dt²= - A w² sin (wt + Ф)

                 - A w² + 1 /LC  A = 0

                  w = √ (1 / LC)

To find the phase factor, for this we use the initial conditions for t = 0

in the case of condensate for t = or the charge is zero

                 0 = A sin Ф

                  Ф = 0

             

                  q = q₀ sin (wt)

6 0
3 years ago
_______is the product of a force and the time during which the force acts
saul85 [17]

Answer:

impulse is the product of a force and the time during which the force acts

Explanation:

i hope this will help you :)

7 0
3 years ago
On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo
ludmilkaskok [199]

Answer:

a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

Explanation:

a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:

\vec v_{A/B} = \vec v_{A} - \vec v_{B}\\\vec v_{A/B} = 11 \frac{m}{s} \cdot i + 31 \frac{m}{s} \cdot i\\\vec v_{A/B} = 42 \frac{m}{s} \cdot i

42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i

42 m/s, negative direction (to the west).

5 0
3 years ago
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