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erastova [34]
3 years ago
5

Question #6a) You were told to assume that the ball bounced to a height of 1.2 m and that the distance between the bounces measu

red along the floor was 0.5 m. Assume that the height of the bounce were less than before, but the distance between bounces were still the same, and complete the following predictions.The horizontal velocity would be (greater/same/less) before.The time between bounces would be (greater/same/less) before.The magnitude of the acceleration of the ball would be (greater/same/less) before.The maximum vertical velocity (right after the first bounce) would be (greater/same/less) before.b) Which of the following statements are evidence that the motion in the x and y coordinates can be treated separately? Select each accordingly.Evidence/NOT evidence : From the graphs of x(t) and y(t), we can see that acceleration happens only in the y coordinate.Evidence/NOT evidence : The time of flight of a bounced ball depends only on the initial y velocity after the first bounce.Evidence/NOT evidence : The acceleration of free-fall is constant.Evidence/NOT evidence : It takes the same amount of time for a dropped ball to reach the floor as it does for a ball that is launched horizontally from the same height.Evidence/NOT evidence : The component equations of x(t) and vx(t) contain no functions of y or vy, and the component equations of y(t) and vy(t) contain no functions of x or vx.Evidence/NOT evidence : A line fit to vy(t) can be used to find the acceleration in the y direction.
Physics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

Explanation:

In the problem they give the case of a ball that bounces on the vertical axis the height is getting smaller, on the x axis it is the same distance all the time.

Questions about the aspect of the x-axis

- Since the distance traveled between the rebounds is the same, the speed must be the same or constant throughout the entire journey.

- Since the distance and speed are equal, the time between rebounds is the same

- There can be no acceleration because the bounce gap should change, the acceleration is zero all the time

Questions about the Y axis

- The vertical speed of the first boat would be the greatest of all, so it has the highest height

b) Evidence or not Evidence

1  evidence, because the graphs are different, one is a straight line and he gives a parable

2 no evidence, nothing involved on the x axis

3  no evidence, the acceleration on the y axis is independent of the acceleration on the x axis

4  no evidence, the time that is cast is the only change that is the same for both movements

5  evidence, the fact that no mixture of components is found allows the variable to be separated into different equations

6  no evidence, says nothing about the x-axis

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4 0
3 years ago
How can i find the acceleration?(rope and grinder have no weight) *** sorry for my english
Finger [1]
The main formula to be used here is

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We'll get to work in just a second.  But first, I must confess to you that I see
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On the <u>right</u> side ... where the 2 kg and the 3 kg are hanging over the same
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I think I can handle the 10 kg, and work out the acceleration that IT has.

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3 years ago
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5.8x10^5N/C=Fe/(1.5x10^-9C)             
Fe=(5.8x10^5N/C)(1.5x10^-9C)
Fe=8.7x10^-4N

Fe=kq1q2/r²
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r²=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/(8.7x10^-4N)
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5 0
3 years ago
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lbvjy [14]

Answer:

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