<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
Answer:
Force, 
Explanation:
Given that,
A potential energy function for a system in which a two-dimensional force acts is of the form of :
We need to find the force that acts at the point (x, y). The force in 2 dimensional with components is given by :
So, the force acting at the point (x,y) is 
. Hence, this is the required solution.
Yes it will thats the same question I got
Answer:
L = 0.99 m = 99 cm
Explanation:
The period is the reciprocal of the frequency.
T = 1/0.5 = 2.0 s
T = 2π√(L/g)
L = g(T/2π)²
L = 9.8(2.0/2π)² = 0.99 m
If the system accelerates upward, it will cause the apparent gravity to increase. This will require a longer pendulum to keep the same period, or shorten the period if the length remains the same. This shows up in the equation where the product of gravity and the square of the period must remain constant for the length to remain constant.
