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adelina 88 [10]
3 years ago
11

A simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top

speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.2 m/s in 2.14 s, what will be his total time?
Physics
1 answer:
Trava [24]3 years ago
6 0

Answer:

He will complete the race in total time of T = 10 s

Explanation:

Total distance moved by the sprinter in 2.14 s is given as

s = \frac{(v_{in} + v_{f})}{2} time

s = \frac{(0 + 11.2)}{2} (2.14)

s = 11.98 m

now the distance remaining to move

d = 100 - 11.98 = 88 m

now he will move with uniform maximum speed for the remaining distance

so we will have

time = \frac{d}{v}

time = \frac{88}{11.2} = 7.86 s

so the total time to complete the race is given as

T = 7.86 + 2.14 = 10 s

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A woman is 160160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing up
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This question is incomplete, the complete question is;

A woman is 160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright.

Hint: Consider the ray diagram below, of the rays that enable her to see her feet and the top of her head.

Use what you know about the law of reflection, together with a bit geometry.

The missing Image is uploaded along this answer below.

Answer:

the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

Explanation:

Given the data in the question and illustrated in the image below,

From image 2;

The distance from the woman's eyes to the top of her head is represented as b and a represent the distance from her eyes to her feet.

Therefore, since her height is 160 cm

a + b = 160 ------ let this be equation 1

i.e AD + DG = 160 cm

Now, from the same image 2, we will notice that triangle ABC and tringle CBD are similar, so

∠ABC = ∠CBD

AC = CD

since AD = a and AC + CD = A

AC = CD = a/2

Also, triangle DEF and FEG are si,ilar

∠DEF = ∠FEG

so

DF = FG

since DG = b and DF + FG = b

DF = b/2

so the minimum vertical length of a mirror in which the woman can see her entire body while standing upright will be;

⇒ a/2 + b/2  

⇒ a + b / 2

from equation 1, a + b = 160

so

⇒ a + b / 2 = 160 / 2 = 80

Therefore, the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

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