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adelina 88 [10]
3 years ago
11

A simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top

speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.2 m/s in 2.14 s, what will be his total time?
Physics
1 answer:
Trava [24]3 years ago
6 0

Answer:

He will complete the race in total time of T = 10 s

Explanation:

Total distance moved by the sprinter in 2.14 s is given as

s = \frac{(v_{in} + v_{f})}{2} time

s = \frac{(0 + 11.2)}{2} (2.14)

s = 11.98 m

now the distance remaining to move

d = 100 - 11.98 = 88 m

now he will move with uniform maximum speed for the remaining distance

so we will have

time = \frac{d}{v}

time = \frac{88}{11.2} = 7.86 s

so the total time to complete the race is given as

T = 7.86 + 2.14 = 10 s

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F=9*10^9*(q0q1)/ r^2

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True or false. Atoms of a given element will have the same mass.
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A grocery cart with a mass of 15 kg is being pushed at constant speed up a 12∘ ramp by a force FP which acts at an angle of 17∘
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A pipe is open at both ends. The pipe has resonant frequencies of 528 Hz and 660HZ (among others).
yawa3891 [41]

To develop this problem it is necessary to apply the oscillation frequency-related concepts specifically in string or pipe close at both ends or open at both ends.

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n = any integer which represent the number of repetition of the spectrum (n)1,2,3...)(Number of harmonic)

Re-arrange to find L,

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The radius between the two frequencies would be 4 to 5,

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4:5

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Here f represents the fundamental frequency.

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Therefore the length of the pipe is 1.3m

For the second harmonic n=2, then

L = \frac{nv}{2f}\\L = \frac{(2)343m/s}{2(132)}\\L = 2.59m

Therefore the length of the pipe in the second harmonic is 2.6m

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