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adelina 88 [10]
3 years ago
11

A simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top

speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.2 m/s in 2.14 s, what will be his total time?
Physics
1 answer:
Trava [24]3 years ago
6 0

Answer:

He will complete the race in total time of T = 10 s

Explanation:

Total distance moved by the sprinter in 2.14 s is given as

s = \frac{(v_{in} + v_{f})}{2} time

s = \frac{(0 + 11.2)}{2} (2.14)

s = 11.98 m

now the distance remaining to move

d = 100 - 11.98 = 88 m

now he will move with uniform maximum speed for the remaining distance

so we will have

time = \frac{d}{v}

time = \frac{88}{11.2} = 7.86 s

so the total time to complete the race is given as

T = 7.86 + 2.14 = 10 s

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Answer:

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Explanation:

Hope this helps!

5 0
3 years ago
I would like to know why this is the correct answer
Helen [10]

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

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Required

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Solution

Newton's 2nd law :

\tt \sum F=m.a

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ΣF=0.8 N

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The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2

  • state 2

ΣF=0.2 N

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The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2

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3 years ago
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\sf\red{hope\:it\:helps\:you}\huge\red{\mid{\underline{\overline{\textbf{Solution\:࿐}}}\mid}}

\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}

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