Answer:
4A
Explanation:
According to ohm's law;
E = IRt where;
E is the source voltage = 24volts
I is the total current flowing in the circuit = ?
Rt is the total effective resistance in the circuit.
To find Rt, we will resolve the resistors in parallel first.
Since 6ohms and 12ohms resistors are in parallel, their effective resistance will give;
1/R = 1/6+1/12
1/R= 2+1/12
1/R = 3/12
3R = 12
R = 4ohms.
This resistor will now be in series with the 2.0ohms resistor to finally have;
Rt = 4+2
Rt = 6ohms
From the ohms law formula;
I = E/Rt
I = 24/6
I = 4Amperes
The total current in the circuit is 4A
This same currents will flow in the 2ohms resistor since same current flows in a series connected resistors.
Answer:
I'm pretty sure the answer is runoff
There diffrent but can cause the same thing
Wending your way through this question and the list of choices
is like running through a corn-maze on a moonless night with
your eyes closed.
Work = (force) x (distance)
Keeping with the units used In the question ...
Work = (90 pounds) x (4 feet) = 360 foot-pounds .
If you want the work expressed in joules, then you need to convert
pounds and feet to newtons and meters.
(90 pounds) x (4.448 newtons/pound) = 400.32 Newtons
(4 feet) x (1 meter / 3.28084 feet) = 1.219 meters
Work = (force) x (distance)
= (400.32 newtons) x (1.219 meters) = 488.1 joules .
Answer: If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.
Explanation:
Radial velocity is defined as the velocity of how an object is seen by the axis of a circle.
Then, if the radial velocity is -50km/s, this means that the radius is decreasing, and then that the star is coming towards the viewer.
as the star is coming towards the viewer, we will see a shorter wavelength, which implies that the frequency would appear to be bigger as it really is.
and this is called a blue shift, because the blue light is the visible light with the biggest frequency, while the red light is the visible light with the smallest frequency, then we have:
If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.
