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3 years ago

How many moles are in 1.84x10^24 formula units of CaCl2, calcium chloride?

1 answer:

7 0

1 mole = 6.022 * 10^23 formula units.

1.84*10^24 formula units CaCl₂ * (1 mole CaCl₂/6.022*10^23 formula units CaCl₂) = 3.06 moles of CaCl₂.

There are 3.06 moles of CaCl₂.

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How many atoms of hydrogen in the product of the equation below:

Luden [163]

Answer: 12 atoms

Explanation: the equation has 6H2 i.e

6*2 = 12

6 0

3 years ago

Drain cleaner has a pH of about 14. How can it be classified, based on its pH?

LUCKY_DIMON [66]

It can be classified as a base

7 0

3 years ago

Read 2 more answers

In an chemicalbreaction involving Fe and S, it was found that 45.2 g of Fes was produced. If the percent yield of the reaction i

saw5 [17]

Answer:

47.8 g

Explanation:

Remember the equation for percent yield:

% yield = actual / theoretical

We're given two of the values in the question, so plug n' play:

0.945 = 45.2 / theoretical

theoretical = 47.8 g

Keep in mind you can use mass here without converting to moles because we're working with products only. If you were given a mass of reactants, you would need to convert to moles and using a balanced chemical equation find the corresponding moles of product produced.

7 0

3 years ago

Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

$Density= \frac{Mass}{Volume}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

3 0

3 years ago

Ex 1) 45.2 g of Zn = _____ moles Zn<br><br> Ex 2) 0.568 moles Ag = _____ grams Ag

Jlenok [28]

the molar mass of Zn is 65

number of mole(n)=reacting mass/molar mass
n=45.2/65
=0.70g/mol

2.the molar mass of Ag is 108

0.568=m/108
then cross multiply
m=0.568×108
m=61.3g

5 0

2 years ago