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Olenka [21]
3 years ago
12

7. A sound wave travels 500m in 60 seconds. Calculate the speed of the sound?

Chemistry
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

8.33m/s

Explanation:

Given parameters:

Distance traveled  = 500m

Time taken  = 60s

Unknown:

Speed of the sound  = ?

Solution:

The speed the sound can be derived using the expression below:

 Speed  = \frac{distance}{time}  

So;

    Speed  = \frac{500}{60}    = 8.33m/s

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If you want to use a serial dilution to make a 1/50 dilution. The first dilution you make is a 1/5 dilution with a total volume
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0.2 mL stock solution, 0.8 solvent, 0.1 mL first solution and 0.9 solvent

Explanation:

The final volume for fist solution is 1 mL and concentration must will be 1/5, then 1 mL/5=0.2 mL. For complete the 1 mL add the missing solvent volume 1 mL-0.2 mL=0.8 mL. For second solution, assuming final volume is 1 mL, and concentration 1/10, then we have 1 mL /10=0.1 mL solution 1/5. Completing volume, 1 mL-0.1 mL= 0.9 mL solvent.

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The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true
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5 0
3 years ago
The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.
Pachacha [2.7K]

Answer : The molecular formula of the compound will be, C_{3}H_{6}O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

n=\frac{\text{molecular mass}}{\text{empirical mass}}

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Molecular formula = (CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3

Thus, the molecular formula of the compound will be, C_{3}H_{6}O_3

7 0
4 years ago
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