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2 years ago

12

7. A sound wave travels 500m in 60 seconds. Calculate the speed of the sound?

1 answer:

Shalnov [3]2 years ago

7 0

Answer:

8.33m/s

Explanation:

Given parameters:

Distance traveled = 500m

Time taken = 60s

Unknown:

Speed of the sound = ?

Solution:

The speed the sound can be derived using the expression below:

Speed = $\frac{distance}{time}$

So;

Speed = $\frac{500}{60}$ = 8.33m/s

You might be interested in

Consider the reaction pathway graph below.

Alex17521 [72]

Hello!

The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ

To calculate Hrxn we apply the following equation:

$Hrxn=Hproducts-Hreagents=-625kJ-(-458kJ)=-167kJ$

Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction releases energy in the form of heat and that the reaction is exothermic.

Have a nice day!

6 0

3 years ago

Calculate the concentration of h3o⁺ in a solution that contains 5.5 × 10-5 m oh⁻ at 25°c. Identify the solution as acidic

Andreas93 [3]

Answer: $[H_3O^+]=1.6\times 10^{-10}M$ , the solution is basic

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

$pH=-\log [H_3O^+]$

$pOH=-\log[OH^-]$

Putting in the values:

$pOH=-\log[5.5\times 10^{-5}]$

$pOH=4.2$

$pH+pOH=14$

$pH=(14-pOH)=(14-4.2)=9.8$

$9.8=-\log [H_3O^+]$

$[H_3O^+]=1.6\times 10^{-10}M$

As pH is more than 7, the solution is basic

7 0

2 years ago

What is the pH of pure water at 40.0Â°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233

Sergeeva-Olga [200]

Answer:

PH= 6.767 (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

$[H_{3}O^{+} ] [OH^{-} ] = Kw = 2.92*10^{-14} M^{2} \\\\$

at 40ºC

$[H_{3}O^{+} ] = [OH^{-} ]$

$[H_{3}O^{+} ]^{2} = 2.92*10^{-14} M^{2}$

$[H_{3}O^{+} ] = (2.92*10^{-14})^{1/2} = 1.71*10^{-7} M$

$PH= -log10[H_{3}O^{+} ] = -log10(1.71*10^{-7} ) = 6.767$

7 0

2 years ago

6.How many moles of gas would be in contained in a 11.2 L container that is at a

qaws [65]

0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated using the following expression:

PV = nRT

Where;

p = pressure (atm)
v = volume (L)
n = number of moles
R = gas law constant
T = temperature

0.75 × 11.2 = n × 0.0821 × 300

8.4 = 24.63n

n = 8.4 ÷ 24.63

n = 0.34 moles

Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

Learn more about number of moles at: brainly.com/question/1190311

4 0

1 year ago

When a certain powder is mixed into a solution of silver nitrate, a white precipitate forms. When the powder is added to a solut

atroni [7]

Answer:

Ammonium chloride

Explanation:

The powder is:- Ammonium chloride

When mixed with silver nitrate, white prescipitate of silver chloride is formed as:-

$NH_4Cl+AgNO_3\rightarrow NH_4NO_3+AgCl$

When mixed with sodium hydroxide, ammonia gas is formed which has noxious order.

$NH_4Cl +NaOH\rightarrow NH_3 + H_2O + NaCl$

Ammonia gas on reaction with nickel (II) hydroxide forms deep blue colored complex as shown below:-

$Ni(OH)_2(s) + 6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}(aq) + 2OH^{-}(aq)$

5 0

2 years ago