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2 years ago

7. A sound wave travels 500m in 60 seconds. Calculate the speed of the sound?

Chemistry

1 answer:

Shalnov [3]2 years ago

7 0

Answer:

8.33m/s

Explanation:

Given parameters:

Distance traveled = 500m

Time taken = 60s

Unknown:

Speed of the sound = ?

Solution:

The speed the sound can be derived using the expression below:

Speed = $\frac{distance}{time}$

So;

Speed = $\frac{500}{60}$ = 8.33m/s

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What is the value of [oh–] in a 0.820 m solution of sr(oh)2?

aniked [119]

Strontium Hydroxide Ionizes as follow,

Sr(OH)₂ → Sr²⁺ + 2 OH⁻
So,
1 mole of Sr(OH)₂ produces 2 moles of Hydroxides,

If the concentration of 1 M Sr(OH)₂ produces 2 M OH⁻ ions then, 0.082 M Sr(OH)₂ will produce,

[OH⁻] = 2 × 0.082

[OH⁻] = 0.164 M

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3 years ago

Enter the net ionic equation for the reaction of aqueous sodium chloride with aqueous silver nitrate.

Ksivusya [100]

An ionic equation refers to a chemical equation where the electrolytes in aqueous solution are demonstrated as dissociated ions. Generally, this is a salt dissolved in water, where the ionic species are succeeded by (aq) in the equation, to suggest that they are in aqueous solution.

Net ionic equation refers to a chemical equation for a reaction that lists only those species that takes part in the reaction. It is an equation, which demonstrates only the reactants taking part in the formation of a precipitate.

In the given case, balanced chemical equations is,

AgNO₃ (aq) + NaCl (aq) = AgCl (s) + NaNO₃ (aq)

Complete ionic equation:

Ag⁺ (aq) +NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) = AgCl (s) + Na⁺ (aq) + NO₃⁻ (aq)

Net Ionic equation:

Ag⁺ (aq) + Cl⁻ (aq) = AgCl (s) (Silver chloride settles as white precipitate)

6 0

2 years ago

Read 2 more answers

Who made the periodic table

TEA [102]

Answer:

Dmitri Mendeleev

Explanation:

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2 years ago

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What do you observe about the movement of the particles in the medium?

horrorfan [7]

Answer:

The particles of the medium just vibrate in place.

Explanation:

As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on. Particles of the medium don't actually travel along with the wave.

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3 years ago

Read 2 more answers

A gaseous mixture composed of 20% CH4, 30% C2H4, 35% C2H2, and 15% C2H20. What is the average molecular weight of the mixture? a

Semenov [28]

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

We are given:

Mass percentage of $CH_4$ = 20 %

So, mole fraction of $CH_4$ = 0.2

Mass percentage of $C_2H_4$ = 30 %

So, mole fraction of $C_2H_4$ = 0.3

Mass percentage of $C_2H_2$ = 35 %

So, mole fraction of $C_2H_2$ = 0.35

Mass percentage of $C_2H_2O$ = 15 %

So, mole fraction of $C_2H_2O$ = 0.15

We know that:

Molar mass of $CH_4$ = 16 g/mol

Molar mass of $C_2H_4$ = 28 g/mol

Molar mass of $C_2H_2$ = 26 g/mol

Molar mass of $C_2H_2O$ = 48 g/mol

To calculate the average molecular mass of the mixture, we use the equation:

$\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}$

where,

$\chi_i$ = mole fractions of i-th species

$m_i$ = molar masses of i-th species

$n_i$ = number of observations

Putting values in above equation:

$\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}$

$\text{Average molecular weight of mixture}=\frac{(0.20\times 16)+(0.30\times 28)+(0.35\times 26)+(0.15\times 42)}{4}\\\\\text{Average molecular weight of mixture}=6.75$

Hence, the correct answer is Option d.

3 0

3 years ago