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3 years ago

During which phase does earth see more than half of the moons surface?

Chemistry

2 answers:

Amanda [17]3 years ago

8 0

Answer:

waxing crescent phase

Verizon [17]3 years ago

8 0

Answer:

Waxing crescent

Explanation:

because i got the question right

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The chemical equation, 2 Cr + 3 Fe(NO3)2 - 3 Fe + 2 Cr(NO3)3, is an

lana66690 [7]

Answer:

Single replacement reaction (aka single displacement reaction)

Explanation:

In a single replacement reaction, one element is substituted for another in a compound to create a new compound and a new element in the products. The general form is:

A + BC --> B + AC

In the case of this question, Cr and Fe "trade places."

6 0

2 years ago

7. Calculate the amount of energy required heat 100.g to <br> H2O(s) changes to H2O(l) at 0°C

Brrunno [24]

Answer:

33300J

Explanation:

Given parameters:

Mass of ice = 100g

Unknown:

Amount of energy = ?

Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

So;

H = mL

m is the mass

L is the latent heat of melting ice

Now, insert the parameters and solve;

H = mL

mass from gram to kilogram;

100g gives 0.1kg

H = 0.1 x 3.33 x 10⁵ = 33300J

8 0

2 years ago

Water has many exceptional and useful properties. Which is the rarest property among compounds?Water has many exceptional and us

dem82 [27]

The density of ice is less than the density of water (liquid). We generally observe that the density of a solid substance is more than its liquid form as volume of a solid is generally less than the liquid, However in case of water this is not true.

The volume of ice is less than that of liquid water due to an open cage like structure in ice which gives its a wide structure. This cage like structure is due to presence of hydrogen bond (more extensive) in ice.

The maximum density of water is observed at 4 degree celsius

5 0

2 years ago

Americans combined drive about 4.0 x 109 kilometers a day and get an average of 20 miles per gallon of gasoline. For each kilogr

Nimfa-mama [501]

Answer:

$303,882.84649 kg\times 3=9.12\times 10^5 kg$ of carbon dioxide gas.

Explanation:

Average distance covered by Americans in a day= $4.0\times 10^9 km$

1 day = 24 × 60 min = 1,440 min

Average distance covered by Americans in a minute= $\frac{4.0\times 10^9 km}{1,440}=2,777,777.78 km$

Average mileage of the car = 20 miles/gal = 32.18 km/gal

1 mile = 1.609 km

20 miles = 20 × 1.609 km = 32.18 km

Volume of gasoline used in minute = $\frac{2,777,777.78 km}{32.18 km/gal}$

$V=86,320.00 gal$

$V=86,320.00\times 3.7854 L$

(1 L = 1000 mL)

$V=86,320.00\times 3.7854 \times 1000 mL=326,755,748.91 mL$

Mass of 86,320.00 gallons of gasoline = m

Density of the gasoline = d = $0.93 g/cm^3=0.93 g/mL$

$1 mL= 1 cm^3$

$m=d\times V=0.93 g/mL\times 326,755,748.91 mL$

$m=303,882,846.49 g=303,882.84649 kg$

1 kilogram of gasoline gives 3 kg of carbon dioxde gas .

Then 303,882.84649 kg of gasoline will give :

$303,882.84649 kg\times 3=9.12\times 10^5 kg$ of carbon dioxide gas.

8 0

2 years ago

Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

7 0

3 years ago