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SCORPION-xisa [38]
3 years ago
9

Which statement describes the charge of an

Chemistry
1 answer:
qwelly [4]3 years ago
6 0
I think that you didn't copy the answers correctly, because 1 and 2 are the same, and 3 and 4 are also the same here.
Anyways, the answer which is correct is that an electron has a charge of -1, and a proton has a charge of +1.
Electrons are negatively charged, whereas protons are positively charged. Neutrons are neutral. 
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Aluminum metal and manganese (IV) oxide react to produce aluminum oxide and manganese metal. What mass of manganese (IV) oxide r
gayaneshka [121]

Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

Explanation:

The balanced chemical equation is:

4Al+3MnO_2\rightarrow 2Al_2O_3+3Mn

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of manganese = \frac{1.12\times 1000g}{55g/mol}=20.4mol

According to stoichiometry :

3 moles of Mn is produced by = 3 moles of MnO_2

Thus 20.4 moles of Mn is produced by =\frac{3}{3}\times 20.4=20.4moles  of MnO_2

Mass of MnO_2=moles\times {\text {Molar mass}}=20.4moles\times 86.9g/mol=1773g=1.773kg    (1kg=1000g)

Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.

6 0
3 years ago
What is the ionic equation of Aqueous calcium bromide was mixed with aqueous gold(I) perchlorate, and a crystallized gold(I) bro
Bumek [7]

Answer:- 2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)

Explanations:- It's a double replacement reaction where a precipitate of silver(I)bromide is formed. A dpuble replacement reaction in general looks as AB + CD \rightarrow AD + CB

To balance the equation we need to multiply gold compounds on both sides by 2 and the balanced equation is..

2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)

6 0
3 years ago
POINTS!!!!
Setler79 [48]
C) 3 Moles
This is because of the molecular structure shown in the image

5 0
3 years ago
What is the answer?
rosijanka [135]
A generator because they connect each other in physical attraction
7 0
3 years ago
Read 2 more answers
"Calculate the number of millimoles in 500 mg of each of the following amino acids: alanine (MW = 89), leucine (131), tryptophan
Cloud [144]

Answer:

- Alanine =  5.61 mmoles

- Leucine = 3.81 mmoles

- Tryptophan = 2.45 mmoles

- Cysteine = 4.13 mmoles

- Glutamic acid = 3.40 mmoles

Explanation:

Mass / Molar mass = Moles

Milimoles = Mol . 1000

500 mg / 1000 = 0.5 g

- Alanine = 0.5 g / 89 g/m → 5.61x10⁻³ moles  . 1000 = 5.61mmoles

- Leucine = 0.5 g / 131 g/m → 3.81 x10⁻³ moles  . 1000 = 3.81 mmoles

- Tryptophan = 0.5 g / 204 g/m →  2.45x10⁻³ moles . 1000 = 2.45 mmoles

- Cysteine = 0.5 g / 121 g/m → 4.13x10⁻³ moles . 1000 = 4.13 mmoles

- Glutamic acid = 0.5 g 147 g/m → 3.40x10⁻³ moles . 1000 =  3.4 mmoles

5 0
3 years ago
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