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madam [21]
3 years ago
10

Is argon gas a pure substance or a mixture. Is iron oxide dust a pure substance or a mixture.

Chemistry
1 answer:
stepladder [879]3 years ago
7 0

Answer:

See below.

Explanation:

Argon gas is a pure substance. It has nothing other than molecules of Argon gas.

Iron oxide is a compound with iron and oxygen as its components. It is a pure substance.

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A horse runs 1 km in 15 s. What is the average speed
Reptile [31]

The average speed of the horse for the entire motion is 66.67 m/s.

The given parameters;

  • <em>distance traveled by the horse, d = 1 km = 1,000 m</em>
  • <em>time of motion of the horse, t = 15 s</em>

The average speed of the horse is calculated by dividing the total distance traveled by the horse by the time of motion.

The average speed of the horse is calculated as follows;

average\ speed = \frac{distance}{time} \\\\average\ speed =  \frac{1000 \ m}{15 \ s} = 66.67 \ m/s

Thus, the average speed of the horse for the entire motion is 66.67 m/s.

Learn more here: brainly.com/question/17289046

6 0
3 years ago
A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the de
docker41 [41]
Displaced volume :

<span> Vf - Vi
</span>
77.0 mL - 50.0 mL => 27 mL

Therefore:

d = m / V

d = 521 / 27

d = 19.29 g/mL

6 0
3 years ago
Dolomite, [CaMg(CO3)2] is found in a soil sample. A geochemist titrates 24.65 g of soil with 57.85 mL of 0.3315M HCl. What is th
pshichka [43]

In order to find out the %mass dolomite in the soil, calculate for the mass of dolomite using the information given from the titration procedure. You would need to multiply 57.85 ml with 0.3315 M HCl and you would get the amount of HCl in millimoles. Then multiply the amount of HCl with 1/2 (given that for every 1 mol of dolomite, 2 mol of HCl would be needed). Convert the amount of dolomite to mass by multiplying the millimoles with the molecular weight which is 184.399. Then convert the mass to grams which is 1.768 grams. Divide the mass of dolomite (1.768 grams) with the weight of soil sample. The % mass is 7.17. 

8 0
3 years ago
Why are most solid ionic compounds electrically nonconductive, whereas aqueous solutions of ionic compounds are good conductors
Allisa [31]

Answer:

there must be free-moving electrons in a compound to conduct electricity.

in solid ionic compounds, there are no free electrons so it can't conduct electricity.

But in aqueous form the forces of attraction are broken and the ions (cations and anions) are free to move. This means there are free electrons that allow the aqueous compound to conduct electricity.

8 0
3 years ago
A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati
Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.  

\text{calculating the initial HI}= \frac{mol}{V}

                                       =\frac{9.3 \times 10 ^ -3}{2}

                                      =0.00465 \ Mol

\text{Similarly}\ \  I_2 \ \  \text{follows} \ \  H_2 = 0 }

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

HI  = 0.00465 - 2x\\\\ I_{2}  \ eq = H_2 \ eq = 0 + x \\\\

It is defined that:

I_2 = 6.29 \times 10^{-4}  \ M \\\\x = I_2 \\\\

HI \ eq= 0.00465 - 2x \\

          =0.00465 -2 \times 6.29 \times 10^{-4} \\\\ =  0.00465 -\frac{25.16 }{10^4}  \\\\   = 0.003392\  M

Now, we calculate the position:  

For the reaction H 2(g) + I 2(g)\rightleftharpoons  2HI(g), you can calculate the value of Kc at 1000 K.  

data expression for Kc

2HI \rightleftharpoons  H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}

         = \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386

calculating the reverse reaction

H_2(g) + I_2(g)\rightleftharpoons  2HI(g)

Kc = \frac{1}{Kc} \\\\

     = \frac{1}{0.034386}\\ \\= 29.081\\

7 0
3 years ago
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