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DerKrebs [107]
3 years ago
9

A star is estimated to be 4.8 km away from the earth. When we see this star in the night sky how old is the image. Let the speed

of light c=3.00 x10^8 m/s.
A. 88 years
B. 500 years
C. 7800 years
D. 16 months
Physics
1 answer:
andre [41]3 years ago
5 0

Time = distance / speed

Time = (4,800 meters) / (3 x 10⁸ m/s)

<em>Time = 0.000016 second</em>

This number is not one of the choices on the list.  My hunch is that you copied the distance wrong.

If the estimated distance to the star is actually 4.8 x 10¹⁵ km, instead of 4.8 km, then the answer would be close to 500 years <em>(B)</em>.

There's no way a star can be "4.8 km away from the Earth".  You can <em>walk</em> that far in about an hour, and passenger jet airplanes fly <em>twice</em> as far as that away from the Earth !

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A 40.0-kg child running at 3.00 m/s suddenly jumps onto a stationary playground merry-go-round at a distance 1.50 m from the axi
satela [25.4K]

Answer:

0.26087 rad/s

Explanation:

mass of the child (m) = 40 kg

velocity (v) = 3 m/s

distance (r) = 1.5 m

moment of inertia (I) = 600 kg.m^{2}

rotational momentum of the child = Iω

where

  • moment of inertia of the child (I) = mr^{2} = 40 x 1.5 x 1.5 = 90 kg/m^{2}
  • angular velocity (ω) = velocity / distance = 3 / 1.5 = 2 rad/s

rotational momentum of the child = Iω = 90 x 2 = 180 kgm^{2}/s

from the conservation of momentum the initial momentum of the child must be the same as the final momentum of the child

initial momentum of the child = final momentum of the child

180 = (90 + 600) ω

180 = 690 ω

ω = 180 / 690 = 0.26087 rad/s

4 0
3 years ago
James Bond is trying to escape his enemy on a speedboat but
SVEN [57.7K]

Answer:

100 m/s

Explanation:

Mass the mass of Bond's boat is m₁. His enemy's boat is twice the mass of Bond's i.e. m₂ = 2 m₁

Initial speed of Bond's boat is 0 as it won't start and remains stationary in the water. The initial speed of enemy's boat is 50 m/s. After the collision, enemy boat is  completely stationary. Let v₁ is speed of bond's boat.

It is the concept of the conservation of momentum. It remains conserved. So,

m_1u_1+m_2u_2=m_1v_1+m_2v_2

Putting all the values, we get :

0+(2m_1)50=m_1v_1+(2m_2)(0)\\\\100m_1=m_1v_1\\\\v_1=100\ m/s

So, Bond's boat is moving with a speed of 100 m/s after the collision.

3 0
4 years ago
How far will an object move in 6 s if its average
Dafna11 [192]

Given:-

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To Find: Distance (s) travelled by the particle.

We know,

s = vt

where,

  • s = Distance travelled,
  • v = Speed &
  • t = Time taken.

Putting the values,

s = (40 m/s)(6 s)

→ s = 240 m ...(Ans.)

6 0
3 years ago
VERY EASY QUESTION FOR HIGH SCHOOL STUDENTS:
Elina [12.6K]

Answer:

Explanation: 6000z

5 0
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What would you need to know to calculate the angular momentum of a man on a Ferris wheel?
valentinak56 [21]
The angular momentum calculated with respect to the axis of rotation of an object is given by:
L=mvr
where m is the object's mass, v is its tangential speed, and r is its distance from the axis of rotation.

In case of a man on a Ferris wheel, we need to have these quantities in order to calculate his angular momentum. These quantities corresponds to:
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- v, the tangential speed of the wheel at its edge
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It is possible to calculate the angular momentum even if we don't know v, the tangential speed. In this case, we need to know at least the angular velocity \omega (because from this relationship we can find the tangential speed: v=\omega r) or the period of rotation of the wheel, T (because we can find the angular velocity from it: \omega= \frac{2 \pi}{T}).
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4 years ago
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