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stiks02 [169]
3 years ago
6

Near the surface of Earth, acceleration due to gravity is 9.8 m/s2. Remember the formula: velocity = acceleration x time. Imagin

e you are in a room with no air, which eliminates fluid friction. Complete the table below for an object that is dropped from rest.

Physics
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:

thats hard what grade is this

Explanation:

AveGali [126]3 years ago
5 0

Answer:

10.8

11.8 and all i know.

Explanation:

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I WILL MARK AS BRAINLIST
puteri [66]

Explanation:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

5 0
3 years ago
A uniform plank of length 6.1 m and mass 33 kg rests horizontally on a scaffold, with 1.6 m of the plank hanging over one end of
salantis [7]

Answer:

Explanation:

consider the principle of moment

when a system is in equilibrium, the clockwise moment (torque) about the pivot is equal to the counterclockwise moment ( torque). Since the plank is uniform the weight of the plank act at the middle which = 6.1 m / 2 = 3.05 m

the distance that can support the weight of the man = d

mass of the man = 70

70 × d = 33 × ( 3.05 - 1.6)

d = 47.85 / 60 = 0.798 m, if the man work beyond this point he will fall.

8 0
3 years ago
A 1000-kg car traveling north at 15 m/s collides with a2000-kg truck traveling east at 10 m/s. The occupants, wearing seat belts
Aleksandr-060686 [28]

Answer:

8.33 m/s, 36.87° North of East

Explanation:

m_n = Mass of car = 1000 kg

v_n = Velocity of car = 15 m/s

m_e = Mass of truck = 2000 kg

v_e = Velocity of truck = 10 m/s

M = Combined mass = 1000+2000 = 3000 kg

Momentum

p_n=m_nv_n\\\Rightarrow p_n=1000\times 15\\\Rightarrow p_n=15000\ kgm/s

Momentum of car traveling East is 15000 kgm/s

p_e=m_ev_e\\\Rightarrow p_n=2000\times 10\\\Rightarrow p_n=20000\ kgm/s

Momentum of truck traveling North is 20000 kgm/s

Angle

\theta=tan^{-1}\frac{p_n}{p_e}\\\Rightarrow \theta=tan^{-1}\frac{15000}{20000}\\\Rightarrow \theta=36.87^{\circ}

As the two vehicles are vectors, the resultant velocity is

(Mv)^2=p_n^2+p_e^2\\\Rightarrow v=\sqrt{\frac{p_n^2+p_e^2}{M^2}}\\\Rightarrow v=\sqrt{\frac{15000^2+20000^2}{3000^2}}\\\Rightarrow v=8.33\ m/s

Velocity of the two vehicles when they are locked together is 8.33 m/s and direction is 36.87° North of East

5 0
3 years ago
A scale reads 184 N when a piece of copper is hanging from it. What does it read (in N) when it is lowered so that the copper is
3241004551 [841]

Answer:

  163 N

Explanation:

The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.

  0.8884 × 184 N ≈ 163 N

The submerged weight is about 163 N.

4 0
3 years ago
you are about to work some magic with matter. you have a rectangular cube of matter in its solid state. it measures 3 in x 4 in
Elenna [48]

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

The matter in gaseous state can be expanded to occupy the volumes of the container.

<h3>Volume of each of the container</h3>

The volume of each of the container is calculated as follows;

<h3>Volume of the rectangular container</h3>

V = 5 in x 6 in x 3 in

V = 90 in³

<h3>Volume of the cylindrical container</h3>

V = πr²h

V = (π)(2.5 in)²(8 in)

V = 157.1 in³

<h3>Volume of the matter</h3>

Vm = 3 in x 4 in x 5 in

Vm = 60 in³

<h3>Matter in solid and liquid state</h3>

Matter has fixed volume in solid and liquid state.

In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.

<h3>Matter in gaseous state</h3>

Matter has no definite volume in gaseous state.

The matter in gaseous state can be expanded to occupy the volumes of the container.

Learn more about states of matter here:

#SPJ1

6 0
1 year ago
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