You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.
You can use a modified dilution formula to calculate the volume of 30 % sugar.
<em>V</em>_1×<em>C</em>_1 + <em>V</em>_2×<em>C</em>_2 = <em>V</em>_3×<em>C</em>_3
Let the volume of 30 % sugar = <em>x</em> pt. Then the volume of the final 20 % sugar = (5 + <em>x</em> ) pt
(<em>x</em> pt×30 % sugar) + (5 pt×5 % sugar) = (<em>x</em> + 5) pt × 20 % sugar
30<em>x</em> + 25 = 20x + 100
10<em>x</em> = 75
<em>x</em> = 75/10 = 7.5
Answer:
38 L
Explanation:
There is some info missing. I think this is the original question.
<em>Consider the chemical reaction: C(s) + H₂
O(g) ⟶ CO(g) + H₂
(g). How many liters of hydrogen gas is formed from the complete reaction of 15.2 g C? Assume that the hydrogen gas is collected at a pressure of 1.0 atm and a temperature of 360 K.</em>
<em />
Step 1: Write the balanced equation
C(s) + H₂
O(g) ⟶ CO(g) + H₂
(g)
Step 2: Calculate the moles corresponding to 15.2 g of C
The molar mass of C is 12.01 g/mol.

Step 3: Calculate the moles of H₂ produced from 1.27 moles of C
The molar ratio of H₂ to C is 1:1. The moles of H₂ produced are 1/1 × 1.27 mol = 1.27 mol.
Step 4: Calculate the volume of H₂
We will use the ideal gas equation.

(1) • Balanced Equation : 2HgO (s) ---> 2 Hg (l) + O₂ (g)
• Line a is represented by activation energy, or the smallest amount of energy needed for molecules to undergo a chemical reaction.
• Activated complex is the intermediate state during the conversion of reactants into products. In this case it is represented by Hg----O-----O----Hg. The dashed lines indicate that the bond between Hg and O are breaking and their length is increasing and the dashed line between oxygen atoms indicate that the bond is decreasing and bond formation is taking place.
• This reaction is endothermic as the energy of reactants is smaller than the energy of products.
(2) • Balanced Equation : CH₃Br + OH⁻ ---> CH₃OH + Br⁻
• The hydroxide ion reacts with the bromomethane, resulting in a double replacement reaction. The 'CH₃' in 'CH₃Br' joins with the hydroxide ion to form CH₃OH, while the Br breaks off as an ion.
• Take a look at the energy diagram below.
Bohr model is valid only for hydrogen and hydrogen-like species, but quantum mechanical model can explain all elements....
Answer:
1.608
Explanation:
According to Graham's effusion law, the rate of effusion (r) of a gas in inversely proportional to the root square of its molar mass (M). The ratio rNH₃ to rCO₂ is:

If CO₂ and NH₃ are allowed to effuse through a porous membrane under identical conditions, the rate of effusion for NH₃ will be 1.608 times that of CO₂.