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seropon [69]
4 years ago
6

Cells take in carbon dioxide and release energy

Chemistry
1 answer:
Katena32 [7]4 years ago
3 0

Answer:

are you talking about plant cells?

Explanation:

You might be interested in
How many pints of a 30% sugar solution must be added to a 5 pint of a 5% sugar solution to obtain a 20% sugar solution?
ser-zykov [4K]

You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.

You can use a modified dilution formula to calculate the volume of 30 % sugar.

<em>V</em>_1×<em>C</em>_1 + <em>V</em>_2×<em>C</em>_2 = <em>V</em>_3×<em>C</em>_3

Let the volume of 30 % sugar = <em>x</em> pt. Then the volume of the final 20 % sugar = (5 + <em>x</em> ) pt

(<em>x</em> pt×30 % sugar) + (5 pt×5 % sugar) = (<em>x</em> + 5) pt × 20 % sugar

30<em>x</em> + 25 = 20x + 100

10<em>x</em> = 75

<em>x</em> = 75/10 = 7.5

5 0
3 years ago
How many liters of hydrogen gas is formed from the complete reaction of 15.2 g C? Assume that the hydrogen gas is collected at a
ira [324]

Answer:

38 L

Explanation:

There is some info missing. I think this is the original question.

<em>Consider the chemical reaction: C(s) + H₂ O(g) ⟶ CO(g) + H₂ (g). How many liters of hydrogen gas is formed from the complete reaction of 15.2 g C? Assume that the hydrogen gas is collected at a pressure of 1.0 atm and a temperature of 360 K.</em>

<em />

Step 1: Write the balanced equation

C(s) + H₂ O(g) ⟶ CO(g) + H₂ (g)

Step 2: Calculate the moles corresponding to 15.2 g of C

The molar mass of C is 12.01 g/mol.

15.2g \times \frac{1mol}{12.01g} = 1.27 mol

Step 3: Calculate the moles of H₂ produced from 1.27 moles of C

The molar ratio of H₂ to C is 1:1. The moles of H₂ produced are 1/1 × 1.27 mol = 1.27 mol.

Step 4: Calculate the volume of H₂

We will use the ideal gas equation.

P \times V = n \times R \times T\\V = \frac{n \times R \times T}{P} = \frac{1.27mol \times \frac{0.0821atm.L}{mol.K}  \times 360K}{1.0atm}= 38 L

3 0
4 years ago
Chemistry questions below! (●'◡'●)
Pie

(1) • Balanced Equation : 2HgO (s) ---> 2 Hg (l) + O₂ (g)

• Line a is represented by activation energy, or the smallest amount of energy needed for molecules to undergo a chemical reaction.

• Activated complex is the intermediate state during the conversion of reactants into products. In this case it is represented by Hg----O-----O----Hg. The dashed lines indicate that the bond between Hg and O are breaking and their length is increasing and the dashed line between oxygen atoms indicate that the bond is decreasing and bond formation is taking place.

• This reaction is endothermic as the energy of reactants is smaller than the energy of products.

(2) • Balanced Equation : CH₃Br + OH⁻ ---> CH₃OH + Br⁻

• The hydroxide ion reacts with the bromomethane, resulting in a double replacement reaction. The 'CH₃' in 'CH₃Br' joins with the hydroxide ion to form CH₃OH, while the Br breaks off as an ion.

• Take a look at the energy diagram below.

3 0
3 years ago
How does the Bohr's model of the atom differ from the quantum mechanical model?
Tom [10]
Bohr model is valid only for hydrogen and hydrogen-like species, but quantum mechanical model can explain all elements....
5 0
3 years ago
If CO2 and NH3 are allowed to effuse through a porous membrane under identical conditions, the rate of effusion for NH3 will be
vladimir1956 [14]

Answer:

1.608

Explanation:

According to Graham's effusion law, the rate of effusion (r) of a gas in inversely proportional to the root square of its molar mass (M). The ratio rNH₃ to rCO₂ is:

\frac{r_{NH_{3}}}{r_{CO_{2}}} =\sqrt{\frac{M(CO_{2})}{M(NH_{3})}} =\sqrt{\frac{44.01g/mol}{17.03g/mol} } =1.608

If CO₂ and NH₃ are allowed to effuse through a porous membrane under identical conditions, the rate of effusion for NH₃ will be 1.608 times that of CO₂.

8 0
4 years ago
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