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ExtremeBDS [4]
3 years ago
12

Help plz:)))I’ll mark u Brainliest

Chemistry
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

\Delta _{fus}H=205J/g=13.03kJ/mol

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

Q=m*\Delta _{fus}H

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g

Or in kJ/mol:

\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\  \Delta _{fus}H=13026.93J/mol=13.03kJ/mol

Regards!

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