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ExtremeBDS [4]
3 years ago
12

Help plz:)))I’ll mark u Brainliest

Chemistry
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

\Delta _{fus}H=205J/g=13.03kJ/mol

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

Q=m*\Delta _{fus}H

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g

Or in kJ/mol:

\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\  \Delta _{fus}H=13026.93J/mol=13.03kJ/mol

Regards!

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How do you find the pressure in a container if you don't have the temperature? 
BARSIC [14]
It depends on the process.
Like for example if the process is isothermal(temperature is constant), you can use,
PV = constant or P1V1 = P2V2 where P1V1 are initial conditions and P2V2 are final.


For adiabatic process,

PV^gamma = constant or P1V1 ^gamma = P2V2 ^gamma.

where gamma = Cp
                          ------
                           Cv
Cp = specific heat at constant pressure and Cv = specific at constant volume.

Value of Gamma will be given in question.
Hope this helps!


7 0
3 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
3
Zina [86]

Answer:

Explanation:

n CaCO3 = mass / m.wt

             = 500  /( 40 + 12 + 16x 3)

           =   5 mole

n CaO = 5 moles  ( from the balanced equation we have 1:1 moles )

mass of CaO = nCaO X m.wt

                       5 x(  40 +16 )

                 =   280 grams

5 0
3 years ago
A hot object will have ___ kinetic energy
Masja [62]

Answer:

More/ Alot? I think is what you are looking for?

Explanation:

It will definitely have some but I'm not sure on what word you are looking for.

6 0
3 years ago
How is oxygen and nitrogen alike​
11111nata11111 [884]

Answer:

They are both colorless, odorless, and tasteless. They have the same number of valence electrons too. And unbalanced electrons in their valence shell.

Explanation:

3 0
3 years ago
Read 2 more answers
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