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3 years ago

Help plz:)))I’ll mark u Brainliest

Chemistry

1 answer:

emmasim [6.3K]3 years ago

8 0

Answer:

$\Delta _{fus}H=205J/g=13.03kJ/mol$

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

$Q=m*\Delta _{fus}H$

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

$\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g$

Or in kJ/mol:

$\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\ \Delta _{fus}H=13026.93J/mol=13.03kJ/mol$

Regards!

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