Answer: The intermolecular forces increase with increasing polarization of bonds. Boiling point increases with molecular weight, and with surface area. The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds. Intermolecular forces are much weaker than the intramolecular forces of attraction but are important because they determine the physical properties of molecules like their boiling point, melting point, density, and enthalpies of fusion and vaporization.In order from strongest to weakest, the intermolecular forces given in the answer choices are: ion-dipole, hydrogen bonding, dipole-dipole, and Van der Waals forces. Ionic bonding is stronger than any of the given intermolecular forces, but is itself NOT an intermolecular force.
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A substance that is composed of only one kind of atom, and in which cannot be separated into simpler substances are converted into another substance by chemical processes are elements. Some examples are hydrogen, oxygen, iodine, radium, magnesium, etc.
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Answer: 0.64 Moles of Propane
Explanation:
Data:
Moles of Carbon = 1.5 mol
Conversion factor = 7 mol C produces = 3 mol of Propane
Solution:
As we know,
7 moles of Carbon produces = 3 moles of Propane
Then,
1.5 moles of Carbon will produce = X moles of Propane
Solving for X,
X = (1.5 moles × 3 moles) ÷ 7 moles
X = 0.6428571 moles of Propane
Or rounded to two significant figures,
X = 0.64 Moles of Propane
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The concentration in mol/l of reactant after 1.5 s is calculated as follows
from first order integrated equation
In (A)t = - Kt + In (A)o where
At = final concentration =?
A)o =initial concentration =0.27 M
K = constant=0.75
T=temperature = 1.5 s
in( A)t = -0.75(1.5) + in(0.27)
In (A)t =-1.125 +-1.31 =-2.435
In(A)t =-2.435
In (A)t = e
find the e value
( A)t is therefore =0.0876 mol/l
