In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d
ay and he is blown along the following directions: 2.50 km and 45.0° north of west, then 5.00 km and 60.0° south of east, then 1.50 km and 30.0° south of west, then 2.00 km straight east, then 1.00 km and 15.0° east of north, then 3.00 km and 75.0° south of west, and finally 4.50 km straight north.
1. Use a graphical method to find the castaway’s final position relative to the island.
1. Use a graphical method to find the castaway’s final position relative to the island.
1 answer:
Answer:
The vector sum is given as in the attached figures, The resultant position is 2.18 km away from the island at 58.19° South of East.
Explanation:
Step No 01: Select appropriate scale. Here 1cm=1km.
Step No 02: Draw each vector one by one such that the tail of 2nd vector coincides with the head of 1st vector.
Step No 03: After all vectors have been drawn, Draw the resultant vector from tail of first vector to the head of 2nd vector.
Step No 04: Measure the resultant vector via ruler and multiple with the scale.
Step No 05: Measure the angle using the D/Protector.
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Answer:
Capacitance of the second capacitor = 2C
Explanation:
Where A is the area, d is the gap between plates and ε₀ is the dielectric constant.
Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.
We have
Similarly for capacitor 2
Capacitance of the second capacitor = 2C