Question

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the day and he is blown along the following directions: 2.50 km and 45.0° north of west, then 5.00 km and 60.0° south of east, then 1.50 km and 30.0° south of west, then 2.00 km straight east, then 1.00 km and 15.0° east of north, then 3.00 km and 75.0° south of west, and finally 4.50 km straight north.
1. Use a graphical method to find the castaway’s final position relative to the island.

Answer 1

Answer:

The vector sum is given as in the attached figures, The resultant position is 2.18 km away from the island at 58.19° South of East.

Explanation:

Step No 01: Select appropriate scale. Here 1cm=1km.

Step No 02: Draw each vector one by one such that the tail of 2nd vector coincides with the head of 1st vector.

Step No 03: After all vectors have been drawn, Draw the resultant vector from tail of first vector to the head of 2nd vector.

Step No 04: Measure the resultant vector via ruler and multiple with the scale.

Step No 05: Measure the angle using the D/Protector.