Why is it a better to wear a white shirt on a hot summer day instead of a black shirt?
2 answers:
You might be interested in
Answer:
D₂= 167,21 cm : Magnitude of the second displacement
β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement
Explanation:
We find the x-y components for the given vectors:
i: unit vector in x direction
j:unit vector in y direction
D₁: Displacement Vector 1
D₂: Displacement Vector 2
R= resulta displacement vector
D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j
D₂= -D₂(i)-D₂(j)
R= 131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j
We propose the vector equation for sum of vectors:
D₁+ D₂= R
-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j
-51.99i+D₂x(i)=103.23i
D₂x=103.23+51.99=155.22 cm
+142.83j-D₂y(j) =+80.65j
D₂y=142.83-80.65=62.18 cm
Magnitude and direction of the second displacement
D₂= 167.21 cm
Direction of the second displacement
β= 21.8°
D₂= 167,21 cm : Magnitude of the second displacement
β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement
Answer:
r = 0.11 m
Explanation:
The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (), as follows:
(1)
<u>Where:</u>
<em>m: is the proton's mass = 1.67*10⁻²⁷ kg</em>
<em>v: is the proton's velocity</em>
<em>r: is the radius of the proton's orbit</em>
<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>
<em>B: is the magnetic field = 0.040 T </em>
Solving equation (1) for r, we have:
(2)
By conservation of energy, we can find the velocity of the proton:
(3)
<u>Where:</u>
<em>K: is kinetic energy</em>
<em>U: is electrostatic potential energy</em>
<em>ΔV: is the potential difference = 1.0 kV </em>
Solving equation (3) for v, we have:
Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:
Therefore, the radius of the proton's resulting orbit is 0.11 m.
I hope it helps you!