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Vika [28.1K]
3 years ago
5

A man is trying to drag a small tree that he cut down. If the static coefficient

Physics
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

120 N

Explanation: First we shoud consider the forces acted on a tree

Friction foce - acting opposite to the moving direction

Weight - Directly acting downwards

Reaction - Directly acting on upwards

For minimum required force should be equal to the friction force

F = μ R

F = 0.5×480

= 120N

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Answer:

W = 2.3 10² F_{e}

Explanation:

The force of the weight is

         W = m g

         

let's use the concept of density

         ρ= m / v

the volume of a sphere is

         V = \frac{4}{3} π r³

         V = \frac{4}{3} π (1.0 10⁻³)³

         V = 4.1887 10⁻⁹ m³

the density of water ρ = 1000 kg / m³

          m = ρ V

          m = 1000 4.1887 10⁻⁹

          m = 4.1887 10⁻⁶ kg

therefore the out of gravity is

          W = 4.1887 10⁻⁶ 9.8

          W = 41.05 10⁻⁶ N

now let's look for the electric force

           F_e = q E

           F_e = 12 10⁻¹² 15000

           F_e = 1.8 10⁻⁷ N

         

the relationship between these two quantities is

          \frac{W}{F_e} = 41.05 10⁻⁶ / 1.8 10⁻⁷

           \frac{W}{F_e} = 2,281 10²

             

             W = 2.3 10² F_{e}

therefore the weight of the drop is much greater than the electric force

3 0
3 years ago
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Alinara [238K]

Answer:

Explanation:

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3/2=1.5

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