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natta225 [31]
3 years ago
7

___ energy has a slightly longer wavelength than visible light energy and can be felt to the touch

Physics
1 answer:
ladessa [460]3 years ago
3 0
Infra-red radiation has a slightly longer wavelength than red light ...
the longest wavelength that is visible to the human eye.

Although infrared can't be detected by the eye, we do have other
receptors that CAN detect it.  They are some of the nerve endings
in our skin.  When infrared radiation hits these, it produces the feeling
of warmth.  Infrared radiation carries heat energy.
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How do I calculate equilibrant and fx and fy. I don't understand what they are asking
Natasha2012 [34]

(a) The equilibrant C for force of vector A and B is 3.43 N.

(b) The equilibrant C for fx of vector A and B is 2.1 N.

(c) The equilibrant  C, for fy of vector A and B is 2.12 N.

<h3>What is equilibrant force?</h3>

An equilibrant force is a single force that will bring other bodies into equilibrium.

<h3>From configuration 1:</h3>

Vector A: mass = 0.2 kg, θ = 20⁰

Vector B: mass = 0.15 kg, θ = 80⁰

Fx = mg cosθ

Fy = mg sinθ

where;

  • m is mass
  • g is acceleration due to gravity

<h3>Vector A</h3>

Force of A due to its weight

F(A) = mg

F(A) = 0.2 x 9.8 = 1.96 N

Fx = (0.2 x 9.8) cos(20) = 1.84 N

Fy = (0.2 x 9.8) sin(20) = 0.67 N

<h3>Resultant force</h3>

R = √(0.67² + 1.84²)

R = 1.96 N

<h3>Vector B</h3>

Force of B due to its weight

F(B) = mg

F(B) = 0.15 x 9.8

F(B) = 1.47 N

Fx = (0.15 x 9.8) cos(80) = 0.26 N

Fy = (0.15 x 9.8) sin(80) = 1.45 N

<h3>Resultant force </h3>

R = √(0.26² + 1.45²)

R= 1.47 N

<h3>Equilibrant  C of vector A and B</h3>

Equilibrant force:

Force, C = 1.96 N + 1.47 N

Force, C = 3.43 N

Equilibrant FX:

Fx, C = Fx(A) + Fx(B)

Fx, C = 1.84 N + 0.26 N = 2.1 N

Equilibrant FY:

Fy, C = Fy(A) + Fy(B)

Fy, C =0.67 N + 1.45 N = 2.12 N

Learn more about equilibrant force here: brainly.com/question/8045102

#SPJ1

3 0
2 years ago
Can you come up with a mathematical relationship, based on your data that shows the relationship between distance from the charg
zalisa [80]

Answer:

Explanation:

This question appears incomplete because of the absence of the data been talked about in the question. However, there is a general ruling here and it can be applied to the data at hand.

If an increase in the distance of charges (let's denote with "d") causes the electric field strength (let's denote with"E") to increase, then the mathematical representation can be illustrated as d ∝ E (meaning distance of charge is directly proportional to electric field strength).

But if an increase in the distance of the charges causes the electric field strength to decrease, then the mathematical representation can be illustrated as d ∝ 1/E (meaning distance of charge is inversely proportional to electric field strength).

A scatterplot can also be used to determine this. If there is a positive correlation (correlation value is greater than zero but less than or equal to 1) on the graph, then it is illustrated as "d ∝ E" BUT if there is a negative correlation (correlation value is less than zero but greater than or equal to -1), then it can be illustrated as "d ∝ 1/E".

4 0
3 years ago
A long, thin solenoid has 390 turns per meter and a radius of 1.20 cm. The current in the solenoid is increasing at a uniform ra
gtnhenbr [62]

To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.

By definition the induced electromotive force is defined as

\int E dl = -\frac{d\phi}{dt}

\int E dl = -(\frac{dB}{dt})A

Where,

\phi = Electric field

B = Magnetic Field

A = Area

At the theory the magnetic field is defined as,

B = \mu_0 NI

Where,

N = Number of loops

I = current

\mu_0 = Permeability constant

We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then

A = \pi r^2

l = 2\pi r

Replacing at the previous equation we have that

E (2\pi r) = \mu_0 n (\frac{di}{dt})(\pi R^2)

Where,

R = Radius of the solenoid

r = The distance from the axis

Re-arrange to find the current in function of time,

\frac{di}{dt} = \frac{Er}{\mu_0 NR^2}

Replacing our values we have

\frac{di}{dt} = \frac{(8.00*10^{-6})(0.0348)}{(4\pi*10^{-7})(390)(1.2*10^-2)^2}

\frac{di}{dt} = 3.94487A/s

8 0
3 years ago
A cheetah can run from 0 to 70 mph in 2.2 seconds. what is speed in m/s
sattari [20]
70 mph

= 70 * 1600 m/h

= <span>112000 m/h

-> 112000 m/h

= 112000 /3600 m/s

= 31.111... m/s

= <u>31 m/s (2s.f)</u></span>
7 0
3 years ago
A block of wood weighs 160 N and has a specific gravity of 0.60. To sink it in fresh water requires an additional downward force
AysviL [449]

Answer:

Your answer is: D) 110N

Hope this helped : )

Explanation:

In order for the wood to sink, it's specific gravity must equal 1 (or greater).

Specific gravity = .6 kg/m^3= Mass/volume

F (Newtons or kg x m/s^2) = Mass*9.8m/s^2.  

Therefore, Mass = 160 N / 9.8 m/s^2= 16.32 kg

Volume = Mass/Specific Gravity = 16.32kg/.6 kg/m^3 = 27.2 m^3

Desired Specific gravity = 1 = (Mass + additional force/9.8m/s^2)/Volume = (16.32 kg +X / 9.8m/s^2)/27.2m^3

Solving for the additional force: X = 106.66...N

The answer is D, 110 N will be required to sink the block of wood.

5 0
3 years ago
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