Answer:
16.03m(2dp)
Explanation:
Ep=m x g x h
1100=7.0x 9.8( gravitational field strength) x h
Height= 1100/7.0 x 9.8
=16.03498542
= 16.03m (2dp)
Answer:
<em>The mass of the shotput is 7.37 Kg.</em>
Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object. If the net force is zero, the object keeps moving at the same speed or keeps at rest (v=0).
A force of 140 N is exerted by a shot-putter on a shotput, which gets an acceleration of 19 m/s^2. We are required to calculate the mass of the shotput.
It can be done by solving the equation for m:
Substituting the given values:
m = 7.37 Kg
The mass of the shotput is 7.37 Kg.
Answer:
The speed of the water shoot out of the hole is 20 m/s.
(d) is correct option.
Explanation:
Given that,
Height = 20 m
We need to calculate the velocity
Using formula Bernoulli equation
Where,
v₁= initial velocity
v₂=final velocity
h₁=total height
h₂=height of the hole from the base
Put the value into the formula
Hence, The speed of the water shoot out of the hole is 20 m/s.
It should be S since S stands for students. Giving the team with more members the upper hand. Hope this helps.