Answer:
E
Step-by-step explanation:
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
D. None.
Step-by-step explanation:
Say the obtuse angle is 100 degrees. Since the sum of all angles in a triangle cannot be bigger than 180, it's not possible because 195 (100+95) is greater than 180 degrees. Hope this helps.
Y = -2x - 2...the slope here is -2. A parallel line will have the same slope.
y = mx + b
slope(m) = -2
(4,5)...x = 4 and y = 5
now we sub and find b, the y int
5 = -2(4) + b
5 = -8 + b
5 + 8 = b
13 = b
so ur parallel equation is : y = 2x + 13