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3 years ago

(b) The speed of the vehicle is written as 90 km/h. State the speed in SI unit. Show your working in the space below.

Physics

2 answers:

suter [353]3 years ago

6 0

Answer:

Explanation:I don't say you to mark my ans as brainliest but if it has really helped you plz don't forget to thank me...

cestrela7 [59]3 years ago

5 0

Answer:

90 km/h = 25 m/ s

Explanation:

to understand

1 km = 1000 m

1 h = 60 minutes and since 1 minute = 60 s you can see that 1 h = 60 * 60 s

90 km / h = 90 1000m / 3600 s

90 *1 / 3.6

90/ 3.6

25 m/ s

so 90 km/h = 25 m/ s

(by the way 90 m/s = 3.6 * 90 = 324 km/ h )

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3 years ago

A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally

aivan3 [116]

Answer:

option B

Explanation:

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Can anyone solve these for my by using unit vectors? Can you also please show your work

Oxana [17]

4. The Coyote has an initial position vector of $\vec r_0=(15.5\,\mathrm m)\,\vec\jmath$ .

4a. The Coyote has an initial velocity vector of $\vec v_0=\left(3.5\,\frac{\mathrm m}{\mathrm s}\right)\,\vec\imath$ . His position at time $t$ is given by the vector

$\vec r=\vec r_0+\vec v_0t+\dfrac12\vec at^2$

where $\vec a$ is the Coyote's acceleration vector at time $t$ . He experiences acceleration only in the downward direction because of gravity, and in particular $\vec a=-g\,\vec\jmath$ where $g=9.80\,\frac{\mathrm m}{\mathrm s^2}$ . Splitting up the position vector into components, we have $\vec r=r_x\,\vec\imath+r_y\,\vec\jmath$ with

$r_x=\left(3.5\,\dfrac{\mathrm m}{\mathrm s}\right)t$

$r_y=15.5\,\mathrm m-\dfrac g2t^2$

The Coyote hits the ground when $r_y=0$ :

$15.5\,\mathrm m-\dfrac g2t^2=0\implies t=1.8\,\mathrm s$

4b. Here we evaluate $r_x$ at the time found in (4a).

$r_x=\left(3.5\,\dfrac{\mathrm m}{\mathrm s}\right)(1.8\,\mathrm s)=6.3\,\mathrm m$

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