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3 years ago

15

Yssa bought four jumbo babes of Skittles, five jumbo bags of m&ms, and seven jumbo bags of Mike’n’Ikes for $121.50. Each jum

bo bag costs the same amount. How much does one jumbo bag cost?

2 answers:

xxTIMURxx [149]3 years ago

7 0

That would be the total cost divided by the amount of items purchased. That is 121.50÷16=7.60

Oduvanchick [21]3 years ago

3 0

121.50 divided by 16= 7.59

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Two times the least of three consecutive odd integers exceeds three times the greatest by 15

Mariana [72]

Three consecutive odd integers would be x, x+2, and x+4 assuming x is an odd integer. The smallest of these is x. Two times x is 2x. The greatest integer is x+4. Three times this is 3 (x+4), and if you distribute you get 3x+12. If 2x exceeds this by 15, you would make it 3x+12-15. If you add the like terms, 12+(-15) is -3. So, you have 2x=3x-3. Subtract 3x from both sides. 2x-3x is -1x, or -x. Now we have -x=-3. Divide by -, or -1 on both sides. Now we have x=3. You can substitute x for 3 for any of the consecutive odd integers to find their value.

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Which two numbers on the number line have an absolute value of 1.75? Select the location of both numbers on the number line

hram777 [196]

Solution

To find Which two numbers on the number line have sn

absolute value of 1.75 .

Absolute value means " how far a number is from

zero " .

"1.75" is 1.75 away from zero .

and " -1.75" is also 1.75 away from zero .

i.e

| 0 - 1.75 | = 1.75

| 1.75 - 0 | = 1.75

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Read 2 more answers

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

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yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

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Here u go I drew a diagram to help u visualise

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