Answer:
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Answer: Newtons second law of motion: the acceleration of an object is directly related to the net force and inversely related to its mass. ... So, the force/mass ratio (from the equation acceleration = force/mass) is the same for each. Therefore, the acceleration is the same and they reach the ground at the same time.
Explanation:
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Answer:
(a) K.E = 56000 J = 56 KJ, (b) d = 116.618 m
Explanation:
Given:
m = 70 Kg, Vi = 40.0 m/s, Vf= 0 m/s, μk = 0.70
Solution:
(a) K.E. =? J (due to motion of the runner the mechanical energy loss is in the form K.E.)
K.E. = 1/2 m v² = 0.5 ×70 kg × (40.0 m/s)²
K.E = 56000 J = 56 KJ
(b) distance d =? m
W= F × d
∴W = K. E = 56000 J and F= mg μk
K.E. = mg μk × d
so 56000 J = 70 kg × 9.8 m/s² × 0.70 × d
d = 116.618 m
Answer:
F = 0.535 N
Explanation:
Let's use the concepts of energy, at the highest and lowest point of the trajectory
Higher
Em₀ = U = mg y
Lower
= K = ½ m v²
Emo =
mg y = ½ m v2
v = √ 2gy
y = L - L cos θ
v = √ (2g L (1-cos θ))
Now let's use Newton's second law n at the lowest point where the acceleration is centripetal
F = ma
a = v² / r
In turning radius is the cable length r = L
F = m 2g (1-cos θ)
Let's calculate
F = 2 1.25 9.8 (1 - cos 12)
F = 0.535 N