Question

Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. if the charge of object 1 is halved, then the electrostatic force is?

Answer 1

Objects 1 and 2 attract each other with an electrostatic force of 72.0 units. if the charge of object 1 is halved, then the electrostatic force is 36.0 units

Let's understand the answer

The electrostatic force is the force that exists between two charged particles which is given by:

$F = K\frac{Q_{1}Q_{2}}{r^{2}}$

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the distance between the charges

In this problem, the charge of object 2 is doubled, so

$F = K\frac{\frac{Q_{1}}{2} Q_{2}}{r^{2}}$

$F = \frac{K}{2} \frac{Q_{1} Q_{2}}{r^{2}}$

$F = \frac{F_{initial}}{2}$

So, the electrostatic force will be halved.

Since as the initial electrostatic force is

F = 72.0 units

the new force will be

72/2 = 36 units

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