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DanielleElmas [232]
2 years ago
8

Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. if the charge of object 1 is halved, then the elect

rostatic force is?
Physics
1 answer:
vodka [1.7K]2 years ago
8 0

Objects 1 and 2 attract each other with an electrostatic force of 72.0 units. if the charge of object 1 is halved, then the electrostatic force is 36.0 units

Let's understand the answer

The electrostatic force is the force that exists between two charged particles which is given by:

F = K\frac{Q_{1}Q_{2}}{r^{2}}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the distance between the charges

In this problem, the charge of object 2 is doubled, so

F = K\frac{\frac{Q_{1}}{2} Q_{2}}{r^{2}}

F = \frac{K}{2} \frac{Q_{1} Q_{2}}{r^{2}}

F = \frac{F_{initial}}{2}

So, the electrostatic force will be halved.

Since as the initial electrostatic force is

F = 72.0 units

the new force will be

72/2 = 36 units

Learn more about electrostatic force here

brainly.com/question/9774180

#SPJ4

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andreyandreev [35.5K]

The threshold frequency fo of Cesium is 4.83 × 10¹⁴ Hz

<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

\large {\boxed {E = h \times f}}

<em>E = Energi of A Photon ( Joule )</em>

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<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}

\large {\boxed {E = qV + \Phi}}

<em>E = Energi of A Photon ( Joule )</em>

<em>m = Mass of an Electron ( kg )</em>

<em>v = Electron Release Speed ( m/s )</em>

<em>Ф = Work Function of Metal ( Joule )</em>

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<em>V = Stopping Potential ( Volt )</em>

Let us now tackle the problem!

<u>Given:</u>

Φ = 2.1 eV = 2 × 1.60 × 10⁻¹⁹ Joule = 3.20 × 10⁻¹⁹ Joule

<u>Unknown:</u>

fo = ?

<u>Solution:</u>

\Phi = h \times fo

3.20 \times 10^{-19} = 6.63 \times 10^{-34} \times fo

fo = ( 3.20 \times 10^{-19} ) \div ( 6.63 \times 10^{-34} )

\large {\boxed{fo = 4.83 \times 10^{14} ~ Hz} }

<h3>Learn more</h3>
  • Photoelectric Effect : brainly.com/question/1408276
  • Statements about the Photoelectric Effect : brainly.com/question/9260704
  • Rutherford model and Photoelecric Effect : brainly.com/question/1458544
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<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt

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given,

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