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ELEN [110]
3 years ago
13

A proton traveling to the right enters a region of uniform magnetic field that points into the screen. When the proton enters th

is region, it will be..??deflected toward bottom of the screendeflected out of the plane of screendeflected toward top of the screendeflected into plane of screenunaffected in its direction of motion
Physics
1 answer:
muminat3 years ago
8 0

Answer:

deflected toward bottom of the screen

Explanation:

When entering the region with magnetic field, a magnetic force is exerted on the proton. This force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the proton.

The direction of the force can be determined by using the right-hand rule. We have:

- Index finger: direction of the velocity of the proton --> to the right

- Middle finger: direction of the magnetic field --> into the screen

- Thumb: direction of the magnetic force --> toward bottom of the screen

So, the correct answer is

deflected toward bottom of the screen

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C.

The train first sped up, giving it a positive acceleration in the beginning. This eliminates D since that choice states that it begins with a negative acceleration. This also eliminates B since that choice states that the train only had a negation acceleration.

Next, the train slows down, giving it a negative acceleration. We’re looking for the answer choice that starts with a positive acceleration and ends with a negative one. This makes C the correct answer. Hope this helps!
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3 years ago
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Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista
Gennadij [26K]

Answer:

The speed with which the skier was going is approximately 2.9906 m/s

Explanation:

The given parameters are;

The distance the skier slides before coming to rest, s = 12.4 m

The coefficient of friction between the skier and the snow, \mu _k = 0.0368

Therefore, for conservation of energy, we have;

Initial kinetic energy = Work done by the kinetic friction force

Initial kinetic energy = 1/2·m·v²

The work done by the kinetic friction force = \mu _k×m×g×s

Where;

m = The mass of the skier

v = The speed with which the skier was going

g = The acceleration due to gravity = 9.8 m/s²

s = The distance the skier slides before coming to rest = 12.4 m

\mu _k = The kinematic friction = 0.0368

Therefore, for conservation of energy, we have;

1/2·m·v² = \mu _k×m×g×s

1/2·v² = \mu _k×g×s

v² = 2×\mu _k×g×s  = 2 × 0.0368 × 9.8 × 12.4 = 8.943872

v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s

The speed with which the skier was going = v ≈ 2.9906 m/s.

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What? What is being asked?
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4 years ago
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This is the principle of the first Law of Thermodynamics, which relates the work and the transferred energy exchanged in a system through the internal energy, which is neither created nor destroyed, it is only transformed.

In other words: The total energy of a system is always conserved.

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Answer:

Both of them are correct

Explanation:

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