Answer:
a) When R is very small R << r, therefore the term R+ r will equal r and the current becomes
b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes
Explanation:
<u>Solution :</u>
(a) We want to get the consumed power P when R is very small. The resistor in the circuit consumed the power from this battery. In this case, the current I is leaving the source at the higher-potential terminal and the energy is being delivered to the external circuit where the rate (power) of this transfer is given by equation in the next form
P=∈*I-I^2*r (1)
Where the term ∈*I is the rate at which work is done by the battery and the term I^2*r is the rate at which electrical energy is dissipated in the internal resistance of the battery. The current in the circuit depends on the internal resistance r and we can apply equation to get the current by
I=∈/R+r (2)
When R is very small R << r, therefore the term R+ r will equal r and the current becomes
I= ∈/r
Now let us plug this expression of I into equation (1) to get the consumed power
P=∈*I-I^2*r
=I(∈-I*r)
=0
The consumed power when R is very small is zero
(b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes
I=∈/R
The dissipated power due toll could be calculated by using equation.
P=I^2*r (3)
Now let us plug the expression of I into equation (3) to get P
P=I^2*R=(∈/R)^2*R
=∈^2/R
The minimum size copper equipment grounding conductor that is required is ; #4 copper
<h3>Equipment grounding conductor </h3>
An Equipment grounding conductor is a conductive part of ground fault current path which connects the non-conducting metallic parts of the euipment together and also connects the system grounded conductor.
For a copper euipment grounding conductor required to serve a control center connected to a 300 amp over current device the minimum size of copper is #4 copper
Hence we can conclude that The minimum size copper equipment grounding conductor that is required is ; #4 copper.
Learn more about Equipment grounding conductor : brainly.com/question/14124204
Explanation:
Kinetic Energy Formula = ½mv²
- ½×800kg×(23m/s)²
- 400kg×529m²/s²
- 211600 kg•m²/s²
- 211700 joule Answer
From the wording of the question, I'm suspecting that you have ...
... either a piece of equipment or else a computer program named "myDAQ",
... an inductor to play with and measure, either in your hand or on the screen.
I have none of these advantages.
In fact, nobody reading this on Brainly has.
It's like if I asked you to write an equation that can be solved to find the total amount of money in all five of my pockets right now.