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The current in the second wire is 1.37 A.
<h3>Current in the second wire</h3>
The current in the second wire is calculated from the magnetic force between the two wires.
F/L = (μI₁I₂)/(2πr)
where;
- μ is permeability of free space
- I₂ is current in the second wire
- F/L is force per unit length
- r is the distance between the two wires
μI₁I₂ = (F/L 2πr)
I₂ = ((F/L 2πr) / (μI₁)
I₂ = (7.7 x ⁻⁵ x 2π x 0.082)/(4π x 10⁻⁷ x 23)
I₂ = 1.37 A
Thus, the current in the second wire is 1.37 A.
Learn more about current here: brainly.com/question/25537936
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Answer:
8/15=0.53..., since the 3 is repeating, just stop at the 4th decimal place, thus
0.5333
Explanation: