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raketka [301]
2 years ago
8

If

Physics
1 answer:
Veronika [31]2 years ago
7 0

Answer:

if what

ha ha

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In order to start an object moving, you must first overcome the force of _________ friction.
navik [9.2K]
It would be static friction which is what you have to overcome when an object is not in motion. When you move an object friction works against it like gravity and air resistance. I hope this helps!
7 0
2 years ago
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if the magnitudes of the forces vary with time as F1=Ct and F = 2Ct, where C equals to 7.5 N/s and t is time, find the time t0 a
Degger [83]

Answer:

The tension in the string is equal to Ct

And the time t0 when the rension in the string is 27N is 3.6s.

Explanation:

An approach to solving this problem jnvolves looking at the whole system as one body by drawing an imaginary box around both bodies and taking summation of the forces. This gives F2 - F1 = Ct. This is only possible assuming the string is massless and does not stretch, that way transmitting the force applied across it undiminished.

So T = Ct

When T = 27N then t = T/C = 27/7.5 = 3.6s

4 0
2 years ago
In a isovolumetric process the is constant.
V125BC [204]

Answer:

An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0.

Explanation:

:)

3 0
3 years ago
A 2.2 m long simple pendulum oscillates with a period of 4.8 s on the surface of unknown planet. What is the surface gravity of
Vsevolod [243]

Answer:

g=3.76\ m/s^2

Explanation:

Given that,

The length of a simple pendulum, l = 2.2 m

The time period of oscillations, T = 4.8 s

We need to find the surface gravity of the planet. The time period of the planet is given by the relation as follows :

T=2\pi \sqrt{\dfrac{l}{g}} \\\\T^2=4\pi ^2\times \dfrac{l}{g}\\\\g=\dfrac{4\pi ^2 l}{T^2}

Put all the values,

g=\dfrac{4\pi ^2 \times 2.2}{(4.8)^2}\\\\=3.76\ m/s^2

So, the value of the surface gravity of the planet is equal to 3.76\ m/s^2.

7 0
3 years ago
What would happen if a rocket ran out of fuel in the Earth's atmosphere?
nydimaria [60]
It would do exactly what a rock or a frisbee does when you toss it.

After the engines cut off, it couldn't get any more energy from
anywhere, and after that, as it pushed air aside to get through,
and had air molecules scraping against it, those would slowly
rob kinetic energy from it.  Sooner or later it would run out of
kinetic energy, start falling, and it would eventually make either
a big 'SPLOOSH' or else a big 'CRUNCH', depending on exactly
where it returned to Earth's surface.
3 0
2 years ago
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