Question

A pump is put into service at the coast where the barometric pressure is 760 mm Hg. The conditions of service are : Flow rate 0,08 m3/s, suction lift 3,5 metres, suction pipe friction loss 0,9 metres, water temperature 65°C, water velocity 4 m/s. Under these conditions of service, the pump requires an NPSH of 2,1 metres. Assuming the density of water as 980,6 kg/m3, establish whether it will operate satisfactorily.

Answer 1

Answer:

The pump operates satisfactorily.

Explanation:

According to the NPSH available definition:

$NPSHa = \frac{P_{a} }{density*g} + \frac{V^{2} }{2g} - \frac{P_{v}}{density*g}$

Where:

$P_{a} absolute pressure at the inlet of the pump$

$V velocity at the inlet of te pump = 4m/s$

$g gravity acceleration = 9,8m/s^{2}$

$P_{v} vapor pressure of the liquid, for water at 65°C = 25042 Pa$

The absolute pressure is the barometric pressure Pb minus the losses: Suction Lift PLift and pipe friction loss Ploss:

To convert the losses in head to pressure:

$P = density*g*H$

So:

$P_{b} = 760 mmHg = 101325 Pa$

$P_{lift} = 33634,58 Pa$

$P_{loss} = 8648,89 Pa$

The absolute pressure:

$P_{a} = P_{b} - P_{lift} - P_{loss} = 59044,53 Pa$

replacing on the NPSH available equiation:

$NPSHa = 6,14 m + 0,816 m - 2,6 m = 4,356 m$

As the NPSH availiable is higher than de required the pump should operate satisfactorily.