Question

Energy is generated uniformly in a 6 cm thick wall. The steady-state temperature distribution

Answer 1

Answer:

Heat generation per unit volume is 45 KW.

Explanation:

Given that

Thickness of wall = 6 cm

Temperature distribution

$T(z)=145+3000z-1500z^2$    -----1

K= 15 W/m.k

As we know that at steady state condition

$\dfrac{d^2T}{dz^2}+\dfrac{q}{K}=0$   -----2

Where q is the heat generation per unit volume.

So from equation 1

$\dfrac{dT}{dz}=3000-3000z$

$\dfrac{d^2T}{dz^2}=-3000$

Now from equation 2

$\dfrac{d^2T}{dz^2}+\dfrac{q}{K}=0$  

$-3000+\dfrac{q}{15}=0$  

So q= 45 KW

So heat generation per unit volume is 45 KW.