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Pepsi [2]
2 years ago
15

Sarah needs to create an architectural drawing for a museum building with an inclined surface. Which presentation view will be t

he best to help the client visualize the design?
Engineering
1 answer:
prohojiy [21]2 years ago
7 0

Answer: auxiliary

Explanation: got it right

You might be interested in
A transmission line (TL) of length L and conductance per unit length G' is connected to an ideal constant voltage generator V. T
Andru [333]

Answer:

The Current will decrease by a factor of 2

Explanation:

Given the conditions, it should be noted that the current in the circuit is determined by the LOAD. In other words, the amount of current generator will be producing depends upon the load connected to it.

Now, as the question says, the load is reduced to half its original value, we can write:

P1 = \sqrt{3} (V) (I1) Cos\alpha ----- (1)

P2 = \sqrt{3} (V) (I2) Cos\alpha\\

Since, P2 = P1/2,

P1/2 = \sqrt{3} (V) (I2) Cos\alpha ----- (2)\\

Dividing equations (1) and (2), we get,

P1 / (P1/2) = I1/ I2

I2 = I1 / 2\\

Hence, it is proved that the current in the transmission line will decrease by a factor of 2 when load is reduced to half.

7 0
3 years ago
For the speed equation along centerline of a diffuser, calculate the fluid acceleration along the diffuser centerline as a funct
Marrrta [24]

Answer:

a = v\cdot \frac{dv}{dx}, v (x) = v_{in}\cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1  \right)\cdot x \right]^{-1}, \frac{dv}{dx} = -v_{in}\cdot \left(\frac{1}{L}\right) \cdot \left(\frac{v_{in}}{v_{out}}-1  \right) \cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}} -1 \right) \cdot x \right]^{-2}

Explanation:

Let suppose that fluid is incompressible and diffuser works at steady state. A diffuser reduces velocity at the expense of pressure, which can be modelled by using the Principle of Mass Conservation:

\dot m_{in} - \dot m_{out} = 0

\dot m_{in} = \dot m_{out}

\dot V_{in} = \dot V_{out}

v_{in} \cdot A_{in} = v_{out}\cdot A_{out}

The following relation are found:

\frac{v_{out}}{v_{in}} = \frac{A_{in}}{A_{out}}

The new relationship is determined by means of linear interpolation:

A (x) = A_{in} +\frac{A_{out}-A_{in}}{L}\cdot x

\frac{A(x)}{A_{in}} = 1 + \left(\frac{1}{L}\right)\cdot \left( \frac{A_{out}}{A_{in}}-1\right)\cdot x

After some algebraic manipulation, the following for the velocity as a function of position is obtained hereafter:

\frac{v_{in}}{v(x)} = 1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1\right) \cdot x

v(x) = \frac{v_{in}}{1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1  \right)\cdot x}

v (x) = v_{in}\cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1  \right)\cdot x \right]^{-1}

The acceleration can be calculated by using the following derivative:

a = v\cdot \frac{dv}{dx}

The derivative of the velocity in terms of position is:

\frac{dv}{dx} = -v_{in}\cdot \left(\frac{1}{L}\right) \cdot \left(\frac{v_{in}}{v_{out}}-1  \right) \cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}} -1 \right) \cdot x \right]^{-2}

The expression for acceleration is derived by replacing each variable and simplifying the resultant formula.

8 0
3 years ago
Read 2 more answers
List, in ascending order, the cutoff frequencies for the first ten modes of a rectangular waveguide, normalized to the cutoff fr
Alisiya [41]

Answer:

Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22

Explanation:

Assuming a = 2b

Attached below is the required steps to the solution

The cutoff frequencies for the first ten modes of a rectangular waveguide listed in ascending order  is :

Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22

5 0
3 years ago
A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid.
Trava [24]

Answer:

a. Heat removal rate will increase

b. Heat removal rate will decrease

Explanation:

Given that

One end of rod is connected to the furnace and rod is long.So this rod can be treated as infinite long fin.

We know that heat transfer in fin given as follows

Q_{fin}=\sqrt{hPKA}\ \Delta T

We know that area

A=\dfrac{\pi}{4}d^2

Now when diameter will triples then :

A_f=\dfrac{\pi}{4}{\left (3d \right )}^2

A_f=9A

Q'_{fin}=\sqrt{9hPKA}\ \Delta T

Q'_{fin}=3\sqrt{hPKA}\ \Delta T

Q'_{fin}=3Q

So the new heat transfer will increase by 3 times.

Now when copper rod will replace by aluminium rod :

As we know that thermal conductivity(K) of Aluminium is low as compare to Copper .It means that heat transfer will decreases.

3 0
3 years ago
Match the descriptions to the respective stage of team
Svetlanka [38]

Answer:

development

forming stage - The team transitions into this stage after completion of its first successful project.

storming stage - In this stage, comfort and trust between the members is high.

norming stage - In this stage, the team members come together for the first time.

performing stage- In this stage, the members have a better idea of what the team expects of them.

5 0
3 years ago
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