Answer:
a) 229.4281 hp.
b) 262.15 ft3/min.
Explanation:
Given data:
P1 = 14.2 psi
T1 = 60°F = 520° R
P2 = 120 psi
T2 = 500°F = 960° R
volumetric flow rate ( Av1 ) = 1200 ft^3 /min = 20 ft^3 / sec
attached below is the detailed solution
Answer:
The solution code is written in Java.
- double [] alpha = new double[50];
-
- for(int i =0; i < 25; i++){
- alpha[i] = i * i;
- }
-
- for(int j = 25; j < 50; j++){
- alpha[j] = j * 3;
- }
Explanation:
Firstly, the syntax to declare an array variable <em>alpha</em> of type double and initialize it with 50 components is presented in Line 1.
Next, use a for-loop to traverse through the first 25 components (Line 3). Use * operator to multiply index variable by itself (to square it) and assign it to the current component of the<em> alpha</em> array (Line 4).
Create another for-loop to traverse through the last 25 components (Line 7). This time, multiply the index variable with 3 and assign it to the current component of the <em>alpha</em> array (Line 8).
Answer:
Factors to be considered when changing or enhancing a design are:
1)The overall aesthetic
2)plausibility
3)cost, and
4 )Efficiency of the new final product.
All these are all important factors to consider.
Answer:
1 . these most common 5 modes of transportation are Railway Road via waterway and pipelines
2 .
Answer:
The overflow rate is 4.24×10^-4 m/s.
The detention time is 7069.5 s
Explanation:
Overflow rate is given as volumetric flow rate ÷ area
volumetric flow rate = 0.3 m^3/s
area = πd^2/4 = 3.142×30^2/4 = 706.95 m^2
Overflow rate = 0.3 m^3/s ÷ 706.95 m^2 = 4.24×10^-4 m/s
Detention time = volume ÷ volumetric flow rate
volume = area × depth = 706.95 m^2 × 3 m = 2120.85 m^3
Detention time = 2120.85 m^3 ÷ 0.3 m^3/s = 7069.5 s