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3 years ago

4. Find the average acceleration of a northbound subway train that slows down from 12 m/s

Mathematics

1 answer:

VikaD [51]3 years ago

5 0

Answer:

-3.125m/s^2

Step-by-step explanation:

Average acceleration = v-u /t

That is initial final velocity v minus initial velocity u divided by the time t In seconds .

From the question,

v =9.5m/s

u =12m/s

t =0.8 secs

Using the above formula,

We have

average a = 9.5 -12 /0.8

= -2.5/0.8

= -3.125m/s^2

Negative answer indicates that the train was decelerating

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Step 3: Let LM = x. We know the lengths of the radii of each circle, so KL = 12 +

kow [346]

Answer:

Step-by-step explanation:

Step 3:

Let LM = x

OK = KP = 12 units [Radii of circle K]

LN = LP = 8 units [Radii of circle L]

Therefore, KL = KP + PL

KL = 12 + 8

= 20 units

Step 4:

Since, ΔKOM and ΔLNM are the similar triangles,

By the property of two similar triangles, corresponding sides of these similar triangles will be proportional.

$\frac{OK}{NL}=\frac{KM}{LM}$

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