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Svet_ta [14]
3 years ago
13

A car accelerates from rest at a constant rate of 2 m/s^2 for 5 s. what is the speed of the car at the end of that time? g

Physics
1 answer:
lara31 [8.8K]3 years ago
5 0
Hope this helps you! This is my step-by-step work. Lemme know if you have any questions!

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A car is traveling at 21.0 m/s. It slows to a stop at a constant rate over 5.00s. How far does the car travel during those 5.00
Doss [256]

Answer:

d = 105 m

Explanation:

Speed of a car, v = 21 m/s

We need to find the distance traveled by the dar during those 5 s before it stops. Let the distance is d. It can be calculated as :

d = v × t

d = 21 m/s × 5 s

d = 105 m

So, it will cover 105 m before it stops.

5 0
3 years ago
A physics student uses a spring loaded launcher to fire a 58 gram projectile horizontally. The projectile leaves the launcher at
timofeeve [1]

Answer:

no answer

Explanation:

the question does not sk what to find

3 0
3 years ago
What is your basal metabolism
Arada [10]
It's the energy your body spends to just keep you breathing and your heart beating ... just being alive, without trying to DO anything.
5 0
3 years ago
Calculate the momentum of a Lion of mass 130-kg and moving at a speed of 22.3 m/s [W]
Sunny_sXe [5.5K]

Answer:

<h2>289.9 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 130 × 22.3

We have the final answer as

<h3>289.9 kg.m/s</h3>

Hope this helps you

3 0
3 years ago
A worker drives a 0.562 kg spike into a rail tie with a 2.26 kg sledgehammer. The hammer hits the spike with a speed of 64.4 m/s
zubka84 [21]

Answer:

Explanation:

Given that,

Mass of sledge hammer;

Mh =2.26 kg

Hammer speed;

Vh = 64.4 m/s

The expression fot the kinetic energy of the hammer is,

K.E(hammer) = ½Mh•Vh²

K.E(hammer) = ½ × 2.26 × 64.4²

K.E ( hammer) = 4686.52 J

If one forth of the kinetic energy is converted into internal energy, then

ΔU = ¼ × K.E(hammer)

∆U = ¼ × 4686.52

∆U = 1171.63 J

Thus, the increase in total internal energy will be 1171.63 J.

4 0
4 years ago
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