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kupik [55]
3 years ago
5

According to Newton's second law of motion what is force equal to

Physics
2 answers:
lubasha [3.4K]3 years ago
8 0
Newton's second law of motion<span> can be formally stated as follows: The acceleration of an object as produced by a net </span>force<span> is directly proportional to the magnitude of the net </span>force, in the same direction as the netforce<span>, and inversely proportional to the mass of the object</span>
IrinaVladis [17]3 years ago
6 0

Explanation:

According to Newton's second law of motion, the force is equal to the product of mass and acceleration of the object. Mathematically, it is given by :

F=m\times a

It is also defined as the rate of change of linear momentum is directly proportional to the applied external force i.e.

F=\dfrac{dp}{dt}

If the momentum of the system is constant, the net force acting on it is equal to 0. Hence, this is the required solution.    

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Just as a skydiver steps out of the helicopter with no forward velocity someone who’s watching start stopwatch so the time is ze
Kobotan [32]

Answer: zero.


Justification:


The downward velocity of the sky diver just before starting to fall is zero, assuming that the helicopter is not moving but just hovering.


Before starting to fall, the velocity of the skydiver is the same of the helicopter, which is zero. It is only, once she jumps out of the helicopter that her weight is not supported by the helicopter and so the gravitational force of the Earth attracts the skydiver and she starts to gain velocity at a rate equal to g (around 9.81 m/s²).

6 0
3 years ago
Although the reactions of the calvin cycle do not depend directly on light. True or False
Harlamova29_29 [7]

Answer:

True

Explanation:

The complete question is:

<em>"Although the reactions of the Calvin cycle do not depend directly on light, they do not usually occur at night. True o False"</em>

<em> </em>The Calvin cycle is also known as the Calvin-Benson cycle or as the CO₂ fixation phase in the photosynthesis process.

The Calvin cycle generates the reactions necessary to fix the carbon in a solid structure for the formation of glucose and, in turn, regenerates the molecules for the continuation of the cycle.

The Calvin cycle is known as the dark phase of photosynthesis, or the carbon fixation phase. It is called the dark phase because this cycle is not dependent on light like other parts that make up the photosynthesis process. But it uses the energy that is produced in the light phase of photosynthesis to fix carbon.

It can be said that it consists of or forms the second stage of photosynthesis, in which the carbon of the carbon dioxide that is absorbed is fixed.

So, the statement is true because the Calvin cycle uses the energy that is produced in the light phase of photosynthesis to fix carbon.

4 0
3 years ago
A record spins at 33 rpm (revolutions per minute), which is an angular velocity of about 3.46 radians per second. What is the ap
lubasha [3.4K]

Hi there!

We can use the following equation to relate angular velocity to linear velocity.

v = \omega r

v = linear velocity (m/s)

ω = angular velocity (3.46 rad/sec)

r = distance from axis of rotation (.12 m)

Plug in the given values.

v = (3.46)(.12) = \boxed{.415 \frac{m}{s}}

6 0
2 years ago
An unmanned spacecraft is in a circular orbit around the moon, observing the lunar surface from an altitude of 43.0 km . To the
GalinKa [24]

Answer: v₂ = 5962 km

the spacecraft  will crash into the lunar surface at a speed of 5962 km if nothing is done to correct its orbits

Explanation:

Given that;

Lunar surface is in an altitude h = 43.0 km =  43 × 10³ m

we know; Radius of moon R₁ = 1.74 × 10⁶, mass of moon = 7.35 × 10²²

speed of the space craft when it crashes into the lunar surface , v

decreasing speed of the space craft = 23 m/s

Now since the space craft travels in a circular orbit, we use centrifugal expression Fe = mv²/r

but the forces is due to gravitational forces between space craft and lunar surface Fg = GMn/r²

HERE r = Rm + h

we substitute

r = 1.74 × 10⁶ m + 43 × 10³ m

= 1.783 × 10⁶ m

On equating these, we have

G is gravitational force ( 6.673 × 10⁻¹¹ Nm²/kg²)

v²/r = GM/r²

v = √ ( GM/r)

v = √ ( 6.673 × 10⁻¹¹ Nm²/kg² × 7.35 × 10²² / 1.783 × 10⁶ )

v = √ (2750787.9978)

v = 1658.55 m/s

Now since speed is decreasing by 23 m/s

the speed of the space craft into the lunar face is,

v₁ = 1658.55 m/s - 23 m/s

v₁ = 1635.55 m/s

Now applying conversation of energy, we say

1/2mv₂² = 1/2mv₁² + GMem (1/Rm - 1/r)

v₂ =  √ [ v₁² + GMe (1/Rm - 1/r)]

v₂ =   √ [ 1635.55²  + ( 6.673 × 10⁻¹¹ Nm²/kg² × 7.35 × 10²²) (1/ 1.74 × 10⁶ - 1 / 1.783 × 10⁶)]

v₂ =  √ (2675023.8025 + 67979.24)

v₂ = √(2743003.046)

v₂ = 1656.2 m/s

now convert

v₂ = 1656.2 × 1km/1000m × 3600s/1hrs

v₂ = 5962 km

Therefore the spacecraft  will crash into the lunar surface at a speed of 5962 km if nothing is done to correct its orbits

8 0
3 years ago
A car with an initial speed of 6.5 m/s accelerates at a uniform rate of 0.92 m/s2 for 3.6 s. Find the final speed of the car dur
geniusboy [140]
U = 6.5 m/s, initial speed
t = 3.6 s, time
a = 0.92 m/s², acceleration

Let v = the final velocity.
Then
v = u +at
v = (6.5 m/s) + (0.92 m/s²)*(3.6 s) = 9.812 m/s

Answer: 9.81 m/s 
8 0
3 years ago
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