Answer:
1600 N
Explanation:
F-F' = ma.................. Equation 1
Where F = Force exerted by the engine, F' = Frictional Force, m = mass of the car, a = acceleration of the car.
make F' the subject of the equation
F' = F-ma............... Equation 2
Given: F = 1600 N, m = 880 kg, a = 0 m/s (moving with a constant velocity).
Substitite these values into equation 2
F' = 1600+880(0)
F' = 1600 N.
Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
The electric field at any point in the region between the conductors is proportional to the magnitude Q of charge on each conductor. It follows that:
"The potential difference Vab between the conductors is also proportional to Q"
If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:

Given that:

and
Lastly, the capacitance is given by:
13.06m
Explanation:
Given parameters:
initial velocity u = 0
final velocity v = 16m/s
Unknown;
height of the hill = ?
Solution:
We are going to apply one of the laws of motion to solve this problem;
V² = U² + 2gH
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
H is the height
since initial velocity is zero;
V² = 2gH
To find the height;
H = 
H =
= 13.06m
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