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vazorg [7]
4 years ago
10

How far away is Pluto?

Physics
2 answers:
fgiga [73]4 years ago
4 0
4.7 billion miles or 7.5 billion km far away from Earth.
GaryK [48]4 years ago
3 0
Pluto is 4.67 billion miles away
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A car with a mass of 880 kg is moving on the road with constant velocity. The force exerted by engine is 1600N. What is the fric
vovangra [49]

Answer:

1600 N

Explanation:

F-F' = ma.................. Equation 1

Where F = Force exerted by the engine, F' = Frictional Force, m = mass of the car, a = acceleration of the car.

make F' the subject of the equation

F' = F-ma............... Equation 2

Given: F = 1600 N, m = 880 kg, a = 0 m/s (moving with a constant velocity).

Substitite these values into equation 2

F' = 1600+880(0)

F' = 1600 N.

4 0
3 years ago
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
Mandarinka [93]

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

5 0
3 years ago
A power source of 6.0 V is attached to the ends of a capacitor. The charge is 12 C.
ArbitrLikvidat [17]
The electric field at any point in the region between the conductors is proportional to the magnitude Q of charge on each conductor. It follows that:

"The potential difference Vab between the conductors is also proportional to Q"

If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:

C= \frac{Q}{V_{ab}}

Given that:

V_{ab}=6V and Q=12\mu C 

Lastly, the capacitance is given by:

C= \frac{12\mu C}{6V}=2\mu F 
5 0
3 years ago
Read 2 more answers
a girl rides a sled down a frozen hill. she starts from rest at the top of the hill and reaches a speed of 16 m/s at the bottom
Zolol [24]

13.06m

Explanation:

Given parameters:

initial velocity u = 0

final velocity v = 16m/s

Unknown;

height of the hill = ?

Solution:

We are going to apply one of the laws of motion to solve this problem;

    V² = U² + 2gH

where V is the final velocity

           U is the initial velocity

           g is the acceleration due to gravity = 9.8m/s²

           H is the height

since initial velocity is zero;

          V² = 2gH

   To find the height;

             H = \frac{V^{2g} }{y}

   

              H = \frac{16^{2} }{2 x 9.8} = 13.06m

learn more:

Velocity brainly.com/question/2706228

#learnwithBrainly

5 0
3 years ago
a rifle is fired and recoils when the bullet leaves the gun. this is an example of newton's 3rd law. the force on the bullet is.
Alex_Xolod [135]
The force of the bullet is the same.
3 0
3 years ago
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