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3 years ago

How do salt and water form a solution?

Physics

2 answers:

iogann1982 [59]3 years ago

8 0

It would be D. The solute, salt, must dissolve IN the solvent, water (:

Klio2033 [76]3 years ago

5 0

Answer: The solute, salt must dissolve in the solvent, water.

Explanation:

Solute is defined as the substance which is present in smaller proportion in a solution.

Solvent is defined as the substance which is present in larger proportion in a solution.

Solution is the combination of solute and solvent.

In a solution, a solute will always dissolve in solvent.

We are given:

Salt and water to form a solution. Here, salt is present in smaller proportion, so it is a solute and water is a solvent.

Hence, the solute, salt must dissolve in the solvent, water.

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If it takes Ashley 6.1 seconds to run at an average speed of 5.7 meters per second, what is the distance (in meters) she covers

Softa [21]

Answer:

34.8m

Explanation:

distance = speed x time

6.1 x 5.7 = 34.77

34.8

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3 years ago

The force of gas particles against the walls of a container is called ________

Liono4ka [1.6K]

Answer:

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3 years ago

Two long, parallel wires are attracted to each other by a force per unit length of 350 µN/m. One wire carries a current of 22.5

pishuonlain [190]

Answer

given,

force per unit length = 350 µN/m

current, I = 22.5 A

y = y = 0.420 m

$\dfrac{F}{L}= \dfrac{KI_1I_2}{d}$

$I_2 = \dfrac{F}{L}\dfrac{d}{KI_1}$

$I_2 = 350\times 10^{-6}\times \dfrac{0.42}{2 \times 10^{-7}\times 22.5}$

I₂ = 32.67 A

distance where the magnetic field is zero

$\dfrac{4\pi \times 10^{-7}\times 32.67}{2\pi y_1}=\dfrac{4\pi \times 10^{-7}\times 22.5}{2\pi (0.42-y_1)}$

$y_1 = 0.248\ m$

there the distance at which the magnetic field is zero in the two wire is at 0.248 m.

3 0

3 years ago

Can someone help please

love history [14]

Answer:

The correct answer is 24.

Explanation:

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If the Earth were compressed in such a way that its mass remained the same, but the distance around the equator were just one-ha

vovikov84 [41]

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3 years ago

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