All categories

3 years ago

Anyone get this if you do please help me step by step

Physics

1 answer:

kotegsom [21]3 years ago

5 0

Answer:

$7.95

Explanation:

$5.75 cost per bag ÷ 47 apples = unit cost of $0.1223. thus, each apple cost $ .1223.

.1223 × 65 apples= $7.95

note_rounding apples to .12*65=$7.8

You might be interested in

The acceleration of an object would increase if there was an increase in the

xxMikexx [17]

As per Newton's II law we know that

$F_{net} = ma$

here we know that

$F_{net} = F_{ap} - F_f$

so here we will have

$a = \frac{F_{ap} - F_f}{m}$

so here if we need to increase the acceleration we need to increase the applied force while on increasing the mass or on increasing the friction force the acceleration will decrease.

So here correct answer will be

<em>A) force on the object.</em>

4 0

3 years ago

a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the run

Sergio039 [100]

Answer:

The runner's acceleration was $1\ m/s^2$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

Solving for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:

$\displaystyle a=\frac{9-5}{4}$

$\displaystyle a=\frac{4}{4}=1$

The runner's acceleration was $1\ m/s^2$

5 0

3 years ago

An apple weighs 1.00 N. When you hang it from the end of a long spring of force constant 1.50 N/m and negligible mass, it bounce

Ierofanga [76]

Answer:

2.67 m

Explanation:

k = Spring constant = 1.5 N/m

g = Acceleration due to gravity = 9.81 m/s²

l = Unstretched length

Frequency of SHM motion is given by

$f_s=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

Frequency of pendulum is given by

$f_p=\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}$

Given in the question

$f_p=\dfrac{1}{2}f_s$

$\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}=\dfrac{1}{2}\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}\\\Rightarrow \sqrt{\dfrac{g}{l}}=\dfrac{1}{2}\sqrt{\dfrac{k}{m}}\\\Rightarrow \dfrac{g}{l}=\dfrac{1}{4}\dfrac{k}{m}\\\Rightarrow l=\dfrac{4gm}{k}\\\Rightarrow l=\dfrac{4\times 9.81\times \dfrac{1}{9.81}}{1.5}\\\Rightarrow l=2.67\ m$

The unstretched length of the spring is 2.67 m

6 0

2 years ago

The velocity of an object includes its speed and what

SCORPION-xisa [38]

I believe that the correct answer you are looking for is the distance traveled

5 0

3 years ago

Read 2 more answers

Why electrons flow in a wire when connected to a battery?

vesna_86 [32]

Answer:

The metal atoms in the wire can't move, but their outer electrons can. The force pushes those electrons and they move to further parts of the wire, trying to reach the other end. As the electrons move away, new electrons flow into the wire through the battery to take their place.

Explanation:

6 0

3 years ago