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3 years ago

Explain how attaching the key to a piece of wood could prevent the key from sinking

Physics

2 answers:

amm18123 years ago

5 0

Wood floats, whereas the key doesn’t. If you attach the 2 together than the wood would prevent the key from sinking.

Free_Kalibri [48]3 years ago

3 0

It could prevent the key from sinking because the wood would float.

It floats because it weighs less than amount of water it would have to push out of the glass if it sank. Wood, cork, and ice are all less dense than water, and they float; rocks are more dense, so they sink. A key would also be more dense causing it to sink.

Hope this helps,

Davinia.

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a 2kg object is moving horizontally with a speed of 4 m/s.how much net force is required to keep the object moving at this speed

Elza [17]

If the object is moving in a straight line with constant speed,
that's a description of " acceleration = zero ".

Zero acceleration means zero net force on the object.

NO net force is 'required' to keep an object moving in a straight line
at constant speed. In fact, if there IS any net force on the object,
then either its speed or its direction MUST change ... there's no way
to avoid it.

None of this depends on the object's mass, or on the speed or direction
of its motion.

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3 years ago

What is the minimum force require to move a 5kg wooden crate on a wooden floor?

kolbaska11 [484]

You need to know the coefficient of static friction between a wooden object and a wooden surface. I'll denote it with µ. If you're given a specific value you should obviously use that.

By Newton's second law, the horizontal and vertical net forces are

• net horizontal:

∑ F = p - f = 0

• net vertical:

∑ F = n - w = 0

where

p = magnitude of the pushing force

f = mag. of friction

n = mag. of the normal force

w = weight of the crate

The second equation gives

n = w = (5 kg) (9.8 m/s²) = 49 N

Friction is proportional to the normal force by a factor of µ, so

f = µ (49 N) = 49µ N

To overcome static friction, the push has to exceed this in magnitude, so that

p > 49µ N

For instance, if p = 0.25, then p would need to greater than 12.25 N. (This example isn't particularly helpful, though, since both possibly correct options are larger than 12.25 N...)

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3 years ago

Can work done=mass*acceleration*displacement(work=m*a*s)

Airida [17]

no, work is = force * distance or displacement

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3 years ago

Once the merry-go-round travels at this new angular speed, with what force does the person need to hold on?.

natita [175]

For a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s is mathematically given as

F= 618.9 N

<h3>What is the centripetal force?</h3>

Generally, the equation for the angular speed is mathematically given as

w = v/R

Therefore

w= 4.7/1.8

w= 2.611 rad/s

Where total momentum

Tm= 642.96 + 272.32

Tm= 915.28

and total inertia

Ti= 184 + 246.24

Ti= 430.24

In conclusion, centripetal force

F= mrw^2

F = m*R*w2^2

F = 76*1.8*2.127^2

F= 618.9 N

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a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s in the counter clockwise direction when viewed from above a person with mass m=76 kg and velocity v=4.7 m/s runs on a path tangent to the merry go round once at the merry go round the person jumps on and holds on to the rim of the merry go round angular speed of the merry go round after the person jumps on 2.127 rad/s Once the merry go round travels at this new angular speed with what force does the person need to hold on?

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2 years ago

A ball is dropped from a height h and falls the last half of its distance in 4 seconds. How long does the ball fall? From what h

dlinn [17]

Answer:

How long does the ball fall is t_2 = 13.66 (s).

From what height is the ball originally dropped is h= 913.90 (m).

Explanation:

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3 years ago