Answer:
If the final question is; at what velocity will the first block start to move outward in m/s?

Explanation:
The motion have the velocity that will make the block move using:




μ
Resolving:





Answer:
66.26 m/s
Explanation:
Horizontal velocity, Vx = 55.3 m/s
Vertical velocity, Vy = 36.5 m/s
The value of the resultant velocity is given by the vector sum of the two velocities which are acting at 90°.


V = 66.26 m/s
Thus, the velocity of the vehicle is 66.26 m/s along its descent path.
Answer:
v_f =63 m/s
Explanation:
given,
starting force = 0 N
uniform rate increase to 36 N
time of action of Force = 35 s
mass of the body = 10 Kg
Speed of the object = ?
From the given data
if we plot F-t curve we will get a triangular shape
we know,
Impulse = Area between F-t curve
= (1/2) x base x height
= 0.5 x 35 x 36
= 630 N.s
now use Impulse-momentum theorem
Impulse = change in momentum
630 = 10 x (v_f - vi)
630 = 10 x (v_f - 0)
v_f =63 m/s
Speed of the object at 35 sec is equal to v_f =63 m/s
Answer:
at its centre
Explanation:
The centre of gravity is a point inside the body where entire weight os the body is said to be concentrated. For geometrical symmetric bodies it lies at the geometric centre of the body.
The base ball is a spherical body, so its centre of gravity lies at its centre.